在Django中选择特定字段get_object_or_404 [英] Select specific fields in Django get_object_or_404
问题描述
我在Django中有一个模型,其中包含太多字段。
Ex:
I have a model in Django with too many fields. Ex:
class MyModel(models.Model):
param_1 = models.CharField(max_length=100)
...
param_25 = models.CharField(max_length=100)
<现在,我需要基于id获取详细信息视图。我见过类似的方法
Now I need to get the detail view based on an id. I have seen may methods like,
obj = MyModel.objects.get(pk=5)
obj = MyModel.objects.filter(pk=5)[0]
obj = get_object_or_404(MyModel, pk=1)
最后一个方法最适合,因为我可以在不进行任何代码更改的情况下提供404错误。但是我只需要param_1和param_2。因此,我需要一个类似以下查询:
The last method suits the best as I can provide a 404 error without any code change. But I need only param_1 and param_2. Hence I need a query similar to,
SELECT "param_1" FROM mymodel WHERE pk=1
如何使用get_object_or_404完成此操作?
How can this be done using get_object_or_404?
有人可以帮忙找一下吗
推荐答案
get_object_or_404
的第一个参数可以是模型,管理器或查询集 :
The first argument to get_object_or_404
can be a Model, a Manager or a QuerySet:
必需参数
Required arguments
黄铜
Model类,管理器或QuerySet实例,从中可以通过
获取对象。
A Model class, a Manager, or a QuerySet instance from which to get the object.
因此,您要做的就是传递预先过滤的QuerySet,例如 仅
:
So, all you have to do is pass in a pre-filtered QuerySet, such as the one returned by only
:
obj = get_object_or_404(MyModel.objects.only('param_1', 'param_2'), pk=1)
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