本地字段与名称相似的字段发生冲突 [英] Local field clashes with field of similar name

问题描述

我正在尝试添加一个新的数据库模型，该模型可以让我分组开支，但是在运行python manage.py makemigrations时却遇到了这个问题。

I'm trying to add a new database model that will let me "group" expenses, but am running across this issue when running python manage.py makemigrations

我的虚拟环境如下所示：

My virtual environment looks like this:

Django==1.7.3
argparse==1.2.1
django-braces==1.4.0
django-chartit==0.1
django-crispy-forms==1.4.0
django-debug-toolbar==1.2.2
psycopg2==2.6
six==1.9.0
sqlparse==0.1.14
wsgiref==0.1.2

这是回溯：

    Traceback (most recent call last):
  File "manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 385, in execute_from_command_line
    utility.execute()
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 377, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/core/management/base.py", line 288, in run_from_argv
    self.execute(*args, **options.__dict__)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/core/management/base.py", line 338, in execute
    output = self.handle(*args, **options)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/core/management/commands/makemigrations.py", line 111, in handle
    convert_apps=app_labels or None,
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/db/migrations/autodetector.py", line 42, in changes
    changes = self._detect_changes(convert_apps, graph)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/db/migrations/autodetector.py", line 109, in _detect_changes
    self.old_apps = self.from_state.render(ignore_swappable=True)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/db/migrations/state.py", line 67, in render
    model.render(self.apps)
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/db/migrations/state.py", line 316, in render
    body,
  File "/home/jeff/.virtualenvs/ggc/local/lib/python2.7/site-packages/django/db/models/base.py", line 229, in __new__
    'base class %r' % (field.name, name, base.__name__)
django.core.exceptions.FieldError: Local field u'id' in class 'ExpenseGroup' clashes with field of similar name from base class 'Asset

'

这是模型代码-我尝试将ExpenseGroup模型缩减为只有groupName作为字段，但出现相同的错误。我缺少什么？

This is the model code - I've tried cutting the ExpenseGroup model down to only the groupName as a field but I get the same error. What am I missing?

    class Asset(TimeStampedModel):
        assetName    = models.CharField(max_length=255)
        assetAddress = models.CharField(max_length=255)
        slug         = models.SlugField(max_length=255, blank=True)

        class Meta:
            unique_together = ('assetName', 'assetAddress')

        def __str__(self):
            return self.assetName

        def save(self, *args, **kwargs):
            self.slug = slugify(self.assetName)
            super(Asset, self).save(*args, **kwargs)


class ExpenseGroup(TimeStampedModel):
    groupName          = models.CharField(max_length=255, blank=False)
    expenseName        = models.ForeignKey(Expense, related_name='expenseGroup')

    class Meta:
        unique_together = ('expenseName', 'groupName')

    def __str__(self):
        return self.groupName

    def save(self, *args, **kwargs):
        return super(ExpenseGroup, self).save(*args, **kwargs)



class Expense(TimeStampedModel):
    assetName          = models.ForeignKey(Asset, related_name='assetExpense')
    category           = models.ForeignKey(ExpenseCategory, related_name='expenseCategory')
    expensePeriod      = models.DateTimeField(blank=False)
    expenseName        = models.CharField(max_length=255, blank=False)
    expenseAmount      = models.DecimalField(max_digits=20, decimal_places=2, blank=True)

    class Meta:
        unique_together = ('expenseName', 'expensePeriod')

    def __str__(self):
        return self.expenseName

    def save(self, *args, **kwargs):
        super(Expense, self).save(*args, **kwargs)

推荐答案

这是Django 1.7.3的错误，升级到最新版本即可（当时为1.7.5） ）

It's a bug with Django 1.7.3, upgrade to the latest and you'll be fine (1.7.5 at the time)

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