如何从不同的索引启动forloop.counter [英] how to start the forloop.counter from a different index

问题描述

我有2个独立的forloops，并且我在bothloops中都使用forloop.counter。我想从第一个forloop的结尾开始第二个forloop计数器

I have 2 seperate forloops and i am using forloop.counter in bothloops. I want to start the second forloop counter from the ending of first forloop

{% for i in something1 %}
  <tr>
    <td>{{ forloop.counter }}</td>
    <td>i.username</td>
  </tr>
{% endfor %}
{% for j in something2 %}
  <tr>
    <td>{{ forloop.counter }}</td>
    <td>j.username</td>
  </tr>
{% endfor %}

如果第一个forloop结束于10，那么我想开始来自11.plz帮助的下一个for循环

if the first forloop ends at 10 then i want to start the next for loop from 11.plz help

推荐答案

我对Django不太满意，因此在给出集合的普通Python：

I'm not comfortable with Django, so I show a couple of option in plain Python, given the collections:

something1 = [1,2,3,4]
something2 = [1,2,3,4,5,6,7,8,9,10]

您可以按索引访问对象（与数据库索引不同）：

You can access objects by index (not the same as database index):

i = 1
for e1 in something1:
  print(e1)
  i += 1

for i2 in range(i,len(something2)):
  print(something2[i2])

或切片最后一个集合：

for e1 in something1:
  print(e1)

for e2 in something2[len(something1):-1]:
  print(e2)

当然，最后一个集合必须是最长的。

Of course, the last collection has to be the longest.

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