整数的Django URL模式 [英] Django URL Pattern For Integer

问题描述

我是Python和Django的新手。我将URLPattern添加到urls.py中，如下所示：

I'm new to Python and Django. I added a URLPattern into urls.py as below:

    url(r'^address_edit/(\d)/$', views.address_edit, name = "address_edit"),

我希望我的url接受参数可变长度的整数，例如db表的 id为0、100、1000、99999。但是我发现在上述模式中我只接受一位数字。如果我传递的不是整数而不是1位数字（例如999999），则会显示错误

I want my url accept a parameter of an integer with variable length, E.g. 0, 100, 1000, 99999, for the "id" of a db table. However I found that I only accept only one digits in above pattern. If i pass a integer not 1 digit only (e.g. 999999), it show an error

Reverse for 'address_edit' with arguments '(9999999,)' and keyword arguments '{}' not found. 1 pattern(s) tried: ['address_book/address_edit/(\\d)/$']

我该如何构造URL模式，使程序从URL接受任意数量的数字整数？

How do I construct the URL Pattern that let the program accept any number of digits integer from URL?

推荐答案

RegEx应该具有 + 修饰符，例如

The RegEx should have + modifier, like this

^address_edit/(\d+)/$

引用 Python的RegEx文档，

'+'

导致结果RE匹配先前RE的1个或多个重复。 ab + 将匹配 a ，后跟任何非零数字的 b s;它不会只匹配 a 。

'+'

Causes the resulting RE to match 1 or more repetitions of the preceding RE. ab+ will match a followed by any non-zero number of bs; it will not match just a.

\d 将匹配任何数字（ 0-9 ）。但它只会匹配一次。要匹配两次，可以执行 \d\d 。但是随着接受位数的增加，您需要增加 \d s的数目。但是RegEx有一种更简单的方法。如果您知道要接受的位数，则可以

\d will match any numeric digit (0-9). But it will match only once. To match it twice, you can either do \d\d. But as the number of digits to accept grows, you need to increase the number of \ds. But RegEx has a simpler way to do it. If you know the number of digits to accept then you can do

\d{3}

这将接受三个连续的数字。如果要接受3到5位数字怎么办？正则表达式涵盖了这一点。

This will accept three consecutive numeric digits. What if you want to accept 3 to 5 digits? RegEx has that covered.

\d{3,5}

简单吧？ :)现在，它将只接受3到5个数字（注意：小于3的任何内容也将不匹配）。现在，您要确保最小的1个数字，但最大的可以是任何数字。你会怎么做？只是将范围保持开放状态，像这样

Simple, huh? :) Now, it will accept only 3 to 5 numeric digits (Note: Anything lesser than 3 also will not be matched). Now, you want to make sure that minimum 1 numeric digit, but maximum can be anything. What would you do? Just leave the range open ended, like this

\d{3,}

现在，RegEx引擎将匹配最少3位数字，最大匹配任意数字。如果要匹配最小一位，最大可以是任何数字，那么您会怎么做

Now, RegEx engine will match minimum of 3 digits and maximum can be any number. If you want to match minimum one digit and maximum can be any number, then what would you do

\d{1,}

更正:)即使这样也可以。但是我们有一个简写方式来表示， + 。如文档中所述，它将匹配任何非零数字。

Correct :) Even this will work. But we have a shorthand notation to do the same, +. As mentioned on the documentation, it will match any non-zero number of digits.

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