什么是docker-compose等同于docker run --init？ [英] What's the docker-compose equivalent of docker run --init?

问题描述

根据 https://github.com/krallin/tini#using-tini，tini内置在docker中，可以通过将-init 标志传递给 docker run 来使用。就我而言，我使用的是docker-compose，而不直接调用 docker run 。我该如何传递此标志？

According to https://github.com/krallin/tini#using-tini, tini is built into docker, and can be used by passing the --init flag to docker run. In my case I'm using docker-compose and don't invoke docker run directly. How can I pass this flag?

推荐答案

如果您使用的是 docker-compose版本2 code>，配置参数称为 init 。

If you are using version 2 of docker-compose, the configuration parameter is called init.

示例：

version: '2.2'
services:
  web:
    image: alpine:latest
    init: /usr/libexec/docker-init

请在此处查看更多详细信息： https://docs.docker.com/compose/compose-file/compose-file-v2 /＃init

Please see here for more details: https://docs.docker.com/compose/compose-file/compose-file-v2/#init

如果您使用的是docker-compose版本3，显然此版本已被删除，并且在3.7版中返回。请参考以下票证： https://github.com/docker/docker。 github.io/issues/3149

If you're using docker-compose version 3, apparently this has been removed and returned in version 3.7. Please refer to the following ticket: https://github.com/docker/docker.github.io/issues/3149

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