使用docker映像通过dockerfile构建其他docker映像 [英] Use a docker image to build a different docker image using a dockerfile

问题描述

我正在尝试使用docker文件构建flask应用程序的docker映像。 flask应用程序使用特定sql版本datajoint / mysql的docker映像（使用docker-compose）。但是我收到以下错误：

  / bin / sh：1：泊坞窗：找不到
命令'/ bin / sh -c docker run -v /var/run/docker.sock:/var/run/docker.sock ...'返回了非零代码：127 
  

我也将docker和docker-compose复制到了我的app /目录中。请您帮我如何安装Docker映像并从Docker文件调用Docker。我经历了以下

非常感谢您的帮助。

解决方案

@DavidMaze是正确的，因为 docker-compose 最有可能在主机上并排运行多个Docker容器的最干净的方法。一旦习惯了它的声明，它实际上便是记录本地/原型设置的好方法。

看看此处为提供的参考 docker-compose datajoint / mysql 图片。特别是在您共享的设置中，如果您的 Dockerfile 位于 datajoint-python 所在的目录中，与 docker-compose.yml 相同的目录，您可以像这样实现它：

 版本： 2.4 
服务：
 db：
图片：datajoint / mysql：5.7 
环境：
-MYSQL_ROOT_PASSWORD = simple 
网络：
-主
＃端口：
＃- 3306：3306 
＃卷：
＃-./data:/var/lib/mysql 
 dj：
 build：。 
取决于：
 db：
条件：service_healthy 
环境：
-DJ_HOST = db 
-DJ_USER = root 
-DJ_PASS = simple 
网络：
-主要
网络：
主要：
  

注意：我故意使用 2.X docker-compose 版本的唯一原因是 3.X 版本适用于不需要此类检查的Docker Swarm部署。

I am trying to build a docker image of a flask app using a docker file. The flask app uses a docker image of specific sql version datajoint/mysql (using docker-compose). But I get the following error:

/bin/sh: 1: docker: not found
The command '/bin/sh -c docker run -v /var/run/docker.sock:/var/run/docker.sock ...' returned a non-zero code: 127

I have also copied the docker and docker-compose to my app/ directory. Please can you help me how to install docker image and call docker from a docker file. I have gone through the following link but it doesn't address my problem directly

Dockerfile

# this is an official Python runtime, used as the parent image
FROM python:3.6.5-slim

# set the working directory in the container to /app
WORKDIR /app



# add the current directory to the container as /app
ADD . /app
# execute everyone's favorite pip command, pip install -r
RUN docker run -v /var/run/docker.sock:/var/run/docker.sock ...
RUN ./docker-compose up -d
RUN ./docker run -p 3306:3306 -e MYSQL_ROOT_PASSWORD=simple datajoint/mysql

# add the current directory to the container as /app
ADD . /app


# execute everyone's favorite pip command, pip install -r
RUN pip install --trusted-host pypi.python.org -r requirements.txt
ADD /datajoint-python /datajoint-python
RUN pip install -e ../datajoint-python/
# unblock port 80 for the Flask app to run on
EXPOSE 1234

# execute the Flask app
CMD ["python", "run.py"]

Below is how amy app directory looks like

Any help is greatly appreciated.

解决方案

@DavidMaze is correct in that docker-compose is most likely the cleanest way to run multiple docker containers side-by-side on your host. Once you become accustomed to its declaration, it actually serves as a great way to document local/prototypical setups.

Have a look here at the reference docker-compose provided for the datajoint/mysql image. Specifically in a setup as you shared where you are looking to dockerize datajoint-python, if your Dockerfile is located in the same directory as your docker-compose.yml, you can achieve it simply like this:

version: '2.4'
services:
  db:
    image: datajoint/mysql:5.7
    environment:
    - MYSQL_ROOT_PASSWORD=simple
    networks:
    - main
    #ports:
    #  - "3306:3306"
    #volumes:
    #  - ./data:/var/lib/mysql
  dj:
    build: .
    depends_on:
      db:
        condition: service_healthy
    environment:
    - DJ_HOST=db
    - DJ_USER=root
    - DJ_PASS=simple
    networks:
    - main
networks:
  main:

Note: The only reason I've intentionally utilized a 2.X docker-compose version is that 3.X versions are meant for Docker Swarm deployments where granular checks like these are unneeded.

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