symfony2按属性排序对象的集合 [英] symfony2 sort collection of objects by a property

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问题描述

我有这个实体:

class Categoria {

    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue
     */

    protected $id;

    /** @ORM\Column(type="string", length=100) */
    protected $nom;

    /** @ORM\Column(type="string", length=100) */
    protected $slug;

    /** @ORM\Column(type="decimal", precision=3, scale=0) */
    protected $ordre;

    /** @ORM\Column(type="boolean", nullable=true) */
    protected $actiu=FALSE;

    /** @ORM\Column(type="decimal", precision=4, scale=0, nullable=true) */
    protected $enllaç=null;

    /** @ORM\OneToMany(targetEntity="LoPati\MenuBundle\Entity\subCategoria", mappedBy="categoria", cascade={"persist", "remove"} )*/
     protected $subCategoria; 
public function __construct()
{
    $this->subCategoria = new \Doctrine\Common\Collections\ArrayCollection();

}

/**
 * Add subCategoria
 *
 * @param LoPati\MenuBundle\Entity\subCategoria $subCategoria
 */
public function addsubCategoria(\LoPati\MenuBundle\Entity\subCategoria $subCategoria)
{
    $this->subCategoria[] = $subCategoria;
}

/**
 * Get subCategoria
 *
 * @return Doctrine\Common\Collections\Collection 
 */
public function getSubCategoria()
{
    return $this->subCategoria;
}

class SubCategoria {

/**
 * @ORM\Id
 * @ORM\Column(type="integer")
 * @ORM\GeneratedValue
 */

protected $id;

/** @ORM\Column(type="string", length=100) */
protected $nom;

/** @ORM\Column(type="string", length=100) */
protected $slug;

/** @ORM\Column(type="decimal", precision=3, scale=0) */
protected $ordre;

/** @ORM\Column(type="boolean", nullable=true) */
protected $actiu=FALSE; 

/** @ORM\Column(type="boolean", nullable=true) */
protected $llista=FALSE;

/** @ORM\Column(type="decimal", precision=4, scale=0, nullable=true) */
protected $enllaç=null;

/** @ORM\ManyToOne(targetEntity="Categoria", inversedBy="subCategoria") */

protected $categoria;

在Categoria实体中,我想按 $排序子类别对象的集合ordre

In Categoria entity I would like sort the collection of subcategoria Objects sort by $ordre.

我该怎么做?

谢谢

问候

推荐答案

使用此注释:

/** 
 * @ORM\OneToMany(targetEntity="LoPati\MenuBundle\Entity\subCategoria", mappedBy="categoria", cascade={"persist", "remove"} )
 * @ORM\OrderBy({"order" = "DESC", "id" = "DESC"})
*/
protected $subCategoria;

...

这篇关于symfony2按属性排序对象的集合的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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