在xml节点中保留换行符 [英] Preserving line breaks in xml node

问题描述

我试图将XML节点中的行转换为无序列表，但是我遇到了一些困难。

I'm trying to convert lines in an XML node into an unordered list, however I'm having some difficulty.

以该节点为例：

 <test>
      Line1
      Line2
      Line3
 </test>

我想用PHP将其转换为它

I would like to transform it into this with PHP

 <ul>
      <li>Line1</li>
      <li>Line2</li>
      <li>Line3</li>
 </ul>

我尝试使用DOMDocument和SimpleXML，但是似乎都没有保留换行符。当回显时，节点值如下所示：

I've tried using DOMDocument and SimpleXML, however neither seem to retain the newlines. When echoed, the node value looks like this :

 Line1 Line2 Line3

我还尝试了 explode 以便使包含每行作为元素的数组：

I've also tried explode in order to have an array containing each line as an element :

 $lines = explode( '\n', $node->nodeValue);

但是，它只返回一个元素的数组，所以我不能用

However, it only returns an array with one element, so I can't make an unordered list with it.

我有一种简单的方法吗？

Is there a simple way for me to do this?

谢谢。

推荐答案

您会踢自己。 ’\n’应该是 \n ！这是一个完整的示例：

You're going to kick yourself. '\n' should be "\n"! Here's a full example:

$Dom = new DOMDocument('1.0', 'utf-8');
$Dom->loadXML(
'<test>
    Line1
    Line2
    Line3
</test>');

$value = $Dom->documentElement->nodeValue;
$lines = explode("\n", $value);
$lines = array_map('trim', $lines); // remove leading and trailing whitespace
$lines = array_filter($lines); // remove empty elements

echo '<ul>';
foreach($lines as $line) {
    echo '<li>', htmlentities($line), '</li>';
}
echo '</ul>';

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