从URL下载返回的Zip文件 [英] Download Returned Zip file from URL

问题描述

如果我有一个URL，当在Web浏览器中提交该URL时，会弹出一个对话框来保存一个zip文件，我将如何在Python中捕获并下载该zip文件？

If I have a URL that, when submitted in a web browser, pops up a dialog box to save a zip file, how would I go about catching and downloading this zip file in Python?

推荐答案

大多数人建议使用请求（如果有）和请求 文档建议将此用于从网址下载并保存原始数据：

Most people recommend using requests if it is available, and the requests documentation recommends this for downloading and saving raw data from a url:

import requests 

def download_url(url, save_path, chunk_size=128):
    r = requests.get(url, stream=True)
    with open(save_path, 'wb') as fd:
        for chunk in r.iter_content(chunk_size=chunk_size):
            fd.write(chunk)

由于答案询问有关下载并保存压缩文件，我没有详细介绍读取该压缩文件的方法。

Since the answer asks about downloading and saving the zip file, I haven't gone into details regarding reading the zip file. See one of the many answers below for possibilities.

如果由于某些原因您无权访问请求 ，则可以改用 urllib.request 。

If for some reason you don't have access to requests, you can use urllib.request instead. It may not be quite as robust as the above.

import urllib.request

def download_url(url, save_path):
    with urllib.request.urlopen(url) as dl_file:
        with open(save_path, 'wb') as out_file:
            out_file.write(dl_file.read())

最后，如果您仍在使用Python 2，则可以使用 urllib2 .urlopen 。

Finally, if you are using Python 2 still, you can use urllib2.urlopen.

from contextlib import closing

def download_url(url, save_path):
    with closing(urllib2.urlopen(url)) as dl_file:
        with open(save_path, 'wb') as out_file:
            out_file.write(dl_file.read())

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