错误:结果不是以下位置的数据框: [英] Error: Results are not data frames at positions:
问题描述
我试图在一个相当大的数据帧上运行一个拟合函数,该函数由名为 big_group
和'small_group'
。
特别是,我试图获取 big_group
中每个 small_group
的预测和coefs值。
也就是说,我正在尝试在 do({
函数。
由于缺少数据点或初始参数估计时的奇异梯度矩阵错误,无法拟合此数据的某些组。 / p>
因此,我使用了
OTH,解决此问题后,我遇到了错误说
错误:结果不是位置3的数据帧
有些有关此错误的讨论,但我不知道它如何实现我的问题。
这是我可复制的示例; (此示例与我的真实数据类似,这就是为什么我要构建这样的示例)
library(minpack.lm)
库(dplyr)
set.seed(100)
data.list<-lapply(1:2,function(big_group){
xx<-c(sort(runif(5,1,5)),sort(runif(5,-8,-2)),rep(5,2))## I意向都加了最后两个5获得不合适的组
yy<-sort(runif(12,0,10))
small_group<-rep(c('a','b' ,'c'),times = c(5,5,2))## big_group
df<-data.frame(xx,yy,small_group,big_group)下的小群
df<-df%>%
group_by(big_group,small_group)%>%
do({
#fitting part
fit<-tryCatch(nlsLM(yy〜k * xx / 2 + U,start = c(k = 1,U = 5),data =。,trace = T,
control = nls.lm .control(maxiter = 100)),error = function(e)NULL)
if(!( NULL%in%class(fit))){
new.range<-data.frame(xx = seq(1,10,length.out = nrow(。)))
预测<-预测(fit,newdata = new.range)
coefs<-data.frame(k = coef(fit)[1],U = coef(fit)[2])
data.frame(。,new.range,predicted,coefs,row.names = NULL)##这是我猜错的部分!
}})
})
这就是数据看起来像; @RomanLuštrik
data.list<-lapply(1:2,function(big_group){
xx< -c(sort(runif(5,1,5)),sort(runif(5,-8,-2)),rep(5,2))##我故意将最后两个5加起来得到不合适的组
yy<-sort(runif(12,0,10))
small_group<-rep(c('a','b','c'),times = c(5,5, 2))## big_group
df以下的小组<-data.frame(xx,yy,small_group,big_group)
})
df <-bind_rows(data.list)
> df
xx yy small_group big_group
1 1.685681 1.302889 a 1
2 2.680406 1.804072 a 1
3 3.153395 3.306605 a 1
4 3.995889 3.486920 a 1
5 4.081206 6.293909 a 1
6 -6.333657 6.952741 b 1
7 -5.070164 7.775844 b 1
8 -4.705420 8.273034 b 1
9 -2.708278 8.651205 b 1
10- 2.428970 8.894535 b 1
11 5.000000 9.541577 c 1
12 5.000000 9.895641 c 1
13 1.830856 1.234872 a 2
14 2.964927 2.114086 a 2
15 3.413297 2.299059 a 2
16 4.121434 2.533907 a 2
17 4.536908 3.577738 a 2
18 -6.807926 4.451480 b 2
19 -6.585834 4.637012 b 2
20 -6.350680 5.913211 b 2
21 -6.157485 5.975753 b 2
22 -6.016821 6.471012 b 2
23 5.000000 6.763982 c 2
24 5.000000 9.605731 c 2
这个怎么样?麻烦似乎是迫使传统的R代码与%&%;%
管道一起使用,因此我只是在解决它。
#库和选项---------------------- -----------------------------
库(minpack.lm)
库(dplyr)
set.seed(100)
#创建数据------------------------------- --------------------------
data.list<-lapply(1:2,function(big_group){
xx<-c(sort(runif(5,1,5)),sort(runif(5,-8,-2)),rep(5,2))## I都将最后两个5加到获取不合适的组
yy <--sort(runif(12,0,10))
small_group<-rep(c('a','b',' c'),times = c(5,5,2))## big_group
df中的小组<-data.frame(xx,yy,small_group,big_group)
})
df<-bind_rows(data.list)
#拟合模型--------- --------------------------------------------------
打印(我的理解是,您要为大型组和小型组的每种组合使用单独的模型拟合)
#创建适合水平的组
df $ big_small <-paste0(df $ big_grou p,df $ small_group)
#创建结果对象
df1<-structure(list(xx = numeric(0),yy = numeric(0),small_group = structure(integer( 0)、. Label = c( a,
b, c),class = factor),big_group =整数(0),big_small =字符(0),
xx.1 =数字(0),预测=数字(0),k =数字(0),
U =数字(0)),.名称= c( xx, yy, small_group , big_group,
big_small, xx.1, predicted, k, U),row.names = integer(0),class = data.frame)
#拟合模型,得到结果
for(b_s in unique(df $ big_small)){
fit<-tryCatch(nlsLM(yy〜k * xx / 2 + U,start = c(k = 1,U = 5),data = df [df $ big_small == b_s,],trace = T,
control = nls.lm.control(maxiter = 100)), error = function(e)NULL)
if(!( NULL%in%class(fit))){
new.range<-data.frame( xx = seq(1,10,length.out = nrow(df [df $ bi g_small == b_s,])))
预测<-预测(fit,newdata = new.range)
coefs<-data.frame(k = coef(fit)[1],U = coef(fit)[2])
df1 <-rbind(df1,data.frame(df [df $ big_small == b_s,],new.range,predicted,coefs,row。)。名称= NULL))
}
}
它。 0,RSS = 44.4318,参数。 = 1 5
它。 1,RSS = 0.259895,参数= 1.89421 1.00916
它。 2,RSS = 0.259895,参数。 = 1.89421 1.00916
它。 0,RSS = 81.5517,参数。 = 1 5
它。 1,RSS = 0.256959,参数= 0.912615 8.80728
它。 2,RSS = 0.256959,参数。 = 0.912615 8.80728
它。 0,RSS = 1.76253,参数。 = 1 5
它。 1,RSS = 0.715381,参数= -156.969 400.646
它。 2,RSS = 0.715381,参数。 = -156.969 400.646
它。 0,RSS = 64.766,参数。 = 1 5
它。 1,RSS = 4.27941,参数。 = 3.32947 -1.95395
它。 2,RSS = 4.27941,参数= 3.32947 -1.95395
它。 0,RSS = 137.22,参数。 = 1 5
它。 1,RSS = 0.209219,参数。 = 0.893139 10.0071
它。 2,RSS = 0.209219,参数。 = 0.893139 10.0071
它。 0,RSS = 9.90713,参数。 = 1 5
它。 1,RSS = 0.0626808,参数= -156.67 401.394
它。 2,RSS = 0.0626808,参数= -156.67 401.394
df1
xx yy small_group big_group big_small xx.1预测k U
1 1.225533 2.046122 a 1 1a 1.00 1.9562669 1.8942075 1.009163
2 2.030690 2.803538 a 1 1a 3.25 4.0872502 1.8942075 1.009163
3 2.231064 3.575249 a 1 1a 5.50 6.2182336 1.8942075 1.009163
4 2.874197 3.594751 a 1 1a 7.75 8.3492170 1.8942075 1.009163
5 3.209290 3.984879 a 1 1a 10.00 10.4802004 1.8942075 1.009163
6 -6.978428 5.358112 b 1 1b 1.00 9.2635844 0.9126145 8.807277
7 -5.778077 6.249965 b 1 1b 3.25 10.2902757 0.9126145 8.807277
8 -5.097376 6.690217 b 1 1b 5.50 11.3169671 0.9126145 8.807277
9 -4.720648 6.902905 b 1 1b 7.75 12.3436585 0.9126145 8.807277
10 -3.125584 7.108038 b 1 1b 10.00 13.3703498 0.9126145 8.807277
11 1.685681 1.302889 a 2 2a 1.00 -0.2892182 3.3294688 -1.953953
b 12 2.680406 1.804072 a 2 2a 3.25 3.4564342 3.3294688 -1.953953
13 3.153395 3.306605 a 2 2a 5.50 7.2020866 3.3294688 -1.953953
14 3.995889 3.486920 a 2 2a 7.75 10.9477390 3.3294688 -1.953953
15 4.081206 6.293909 a 2 2a 10.00 14.6933913 3.3294688 -1.953953
16 -6.333657 6.952741 b 2 2b 1.00 10.4536476 0.8931386 10.007078
17 -5.070164 7.775844 b 2 2b 3.25 11.4584286 0.8931386 10.007078
18 -4.705420 8.273034 b 2 2b 5.50 12.4632095 0.8931386 10.007078
19 -2.708278 8.651205 b 2 2b 7.75 13.4679905 0.8931386 10.007078
20 -2.428970 8.894535 b 2 2b 10.00 14.4727715 0.8931386 10.007078
I am trying to run a fitting function on a rather large data frame, grouped by a variable named "big_group"
and 'small_group'
.
In particular, I am trying to get predictions and coefs values of every small_group
inside of big_group
.
That is, I'm trying to add these new columns to my new data.frame at the end of do({
function.
Some of the groups of this data cannot be fitted due to either lack of data points or "singular gradient matrix at initial parameter estimates" error.
So, I used tryCatch
method from this post of how-do-i-ignore-errors-and-continue-processing-list-items and I used following answer of @Koshke
OTH, after solving this issue I come to encounter an error is saying
Error: Results are not data frames at positions: 3
There is some discussions about this error but I could not figure it how to implement to my problem.
Here is my reproducible example; (This example is similar to my real data that's why I built the example like this)
library(minpack.lm)
library(dplyr)
set.seed(100)
data.list <- lapply(1:2, function(big_group) {
xx <- c(sort(runif(5,1,5)),sort(runif(5,-8,-2)), rep(5,2)) ##I intentionall added the last two 5 to get unfitted groups
yy<- sort(runif(12,0,10))
small_group <- rep(c('a','b','c'),times=c(5,5,2)) ##small groups in under the big_group
df <- data.frame(xx,yy,small_group,big_group)
df <- df%>%
group_by(big_group,small_group)%>%
do({
#fitting part
fit <- tryCatch(nlsLM(yy~k*xx/2+U, start=c(k=1,U=5), data = ., trace=T,
control = nls.lm.control(maxiter=100)),error=function(e) NULL)
if(!("NULL" %in% class(fit))){
new.range<- data.frame(xx=seq(1,10,length.out=nrow(.)))
predicted <- predict(fit, newdata =new.range)
coefs <- data.frame(k=coef(fit)[1],U=coef(fit)[2])
data.frame(., new.range,predicted,coefs,row.names=NULL) ##This is the part the error came from I guess!
}})
})
This is what the data looks like; @RomanLuštrik
data.list <- lapply(1:2, function(big_group) {
xx <- c(sort(runif(5,1,5)),sort(runif(5,-8,-2)), rep(5,2)) ##I intentionall added the last two 5 to get unfitted groups
yy<- sort(runif(12,0,10))
small_group <- rep(c('a','b','c'),times=c(5,5,2)) ##small groups in under the big_group
df <- data.frame(xx,yy,small_group,big_group)
})
df <- bind_rows(data.list)
> df
xx yy small_group big_group
1 1.685681 1.302889 a 1
2 2.680406 1.804072 a 1
3 3.153395 3.306605 a 1
4 3.995889 3.486920 a 1
5 4.081206 6.293909 a 1
6 -6.333657 6.952741 b 1
7 -5.070164 7.775844 b 1
8 -4.705420 8.273034 b 1
9 -2.708278 8.651205 b 1
10 -2.428970 8.894535 b 1
11 5.000000 9.541577 c 1
12 5.000000 9.895641 c 1
13 1.830856 1.234872 a 2
14 2.964927 2.114086 a 2
15 3.413297 2.299059 a 2
16 4.121434 2.533907 a 2
17 4.536908 3.577738 a 2
18 -6.807926 4.451480 b 2
19 -6.585834 4.637012 b 2
20 -6.350680 5.913211 b 2
21 -6.157485 5.975753 b 2
22 -6.016821 6.471012 b 2
23 5.000000 6.763982 c 2
24 5.000000 9.605731 c 2
How about this? The trouble seemed to be forcing the traditional R code to work with the %>%
pipe, so I just worked around it.
# Libraries and Options ---------------------------------------------------
library(minpack.lm)
library(dplyr)
set.seed(100)
# Create the data ---------------------------------------------------------
data.list <- lapply(1:2, function(big_group) {
xx <- c(sort(runif(5,1,5)),sort(runif(5,-8,-2)), rep(5,2)) ##I intentionall added the last two 5 to get unfitted groups
yy<- sort(runif(12,0,10))
small_group <- rep(c('a','b','c'),times=c(5,5,2)) ##small groups in under the big_group
df <- data.frame(xx,yy,small_group,big_group)
})
df <- bind_rows(data.list)
# Fit the Model -----------------------------------------------------------
print("My understanding here is that you want a separate model fit for each combination of big group and small group")
# Create fit-level groups
df$big_small <- paste0(df$big_group, df$small_group)
# Create results object
df1 <- structure(list(xx = numeric(0), yy = numeric(0), small_group = structure(integer(0), .Label = c("a",
"b", "c"), class = "factor"), big_group = integer(0), big_small = character(0),
xx.1 = numeric(0), predicted = numeric(0), k = numeric(0),
U = numeric(0)), .Names = c("xx", "yy", "small_group", "big_group",
"big_small", "xx.1", "predicted", "k", "U"), row.names = integer(0), class = "data.frame")
# Fit model, get results
for(b_s in unique(df$big_small)){
fit <- tryCatch(nlsLM(yy~k*xx/2+U, start=c(k=1,U=5), data = df[df$big_small==b_s,], trace=T,
control = nls.lm.control(maxiter=100)),error=function(e) NULL)
if(!("NULL" %in% class(fit))){
new.range<- data.frame(xx=seq(1,10,length.out=nrow(df[df$big_small==b_s,])))
predicted <- predict(fit, newdata =new.range)
coefs <- data.frame(k=coef(fit)[1],U=coef(fit)[2])
df1 <- rbind(df1, data.frame(df[df$big_small==b_s,], new.range,predicted,coefs,row.names=NULL))
}
}
It. 0, RSS = 44.4318, Par. = 1 5 It. 1, RSS = 0.259895, Par. = 1.89421 1.00916 It. 2, RSS = 0.259895, Par. = 1.89421 1.00916 It. 0, RSS = 81.5517, Par. = 1 5 It. 1, RSS = 0.256959, Par. = 0.912615 8.80728 It. 2, RSS = 0.256959, Par. = 0.912615 8.80728 It. 0, RSS = 1.76253, Par. = 1 5 It. 1, RSS = 0.715381, Par. = -156.969 400.646 It. 2, RSS = 0.715381, Par. = -156.969 400.646 It. 0, RSS = 64.766, Par. = 1 5 It. 1, RSS = 4.27941, Par. = 3.32947 -1.95395 It. 2, RSS = 4.27941, Par. = 3.32947 -1.95395 It. 0, RSS = 137.22, Par. = 1 5 It. 1, RSS = 0.209219, Par. = 0.893139 10.0071 It. 2, RSS = 0.209219, Par. = 0.893139 10.0071 It. 0, RSS = 9.90713, Par. = 1 5 It. 1, RSS = 0.0626808, Par. = -156.67 401.394 It. 2, RSS = 0.0626808, Par. = -156.67 401.394
df1
xx yy small_group big_group big_small xx.1 predicted k U 1 1.225533 2.046122 a 1 1a 1.00 1.9562669 1.8942075 1.009163 2 2.030690 2.803538 a 1 1a 3.25 4.0872502 1.8942075 1.009163 3 2.231064 3.575249 a 1 1a 5.50 6.2182336 1.8942075 1.009163 4 2.874197 3.594751 a 1 1a 7.75 8.3492170 1.8942075 1.009163 5 3.209290 3.984879 a 1 1a 10.00 10.4802004 1.8942075 1.009163 6 -6.978428 5.358112 b 1 1b 1.00 9.2635844 0.9126145 8.807277 7 -5.778077 6.249965 b 1 1b 3.25 10.2902757 0.9126145 8.807277 8 -5.097376 6.690217 b 1 1b 5.50 11.3169671 0.9126145 8.807277 9 -4.720648 6.902905 b 1 1b 7.75 12.3436585 0.9126145 8.807277 10 -3.125584 7.108038 b 1 1b 10.00 13.3703498 0.9126145 8.807277 11 1.685681 1.302889 a 2 2a 1.00 -0.2892182 3.3294688 -1.953953 12 2.680406 1.804072 a 2 2a 3.25 3.4564342 3.3294688 -1.953953 13 3.153395 3.306605 a 2 2a 5.50 7.2020866 3.3294688 -1.953953 14 3.995889 3.486920 a 2 2a 7.75 10.9477390 3.3294688 -1.953953 15 4.081206 6.293909 a 2 2a 10.00 14.6933913 3.3294688 -1.953953 16 -6.333657 6.952741 b 2 2b 1.00 10.4536476 0.8931386 10.007078 17 -5.070164 7.775844 b 2 2b 3.25 11.4584286 0.8931386 10.007078 18 -4.705420 8.273034 b 2 2b 5.50 12.4632095 0.8931386 10.007078 19 -2.708278 8.651205 b 2 2b 7.75 13.4679905 0.8931386 10.007078 20 -2.428970 8.894535 b 2 2b 10.00 14.4727715 0.8931386 10.007078
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