行总和使用mutate和select [英] Row sum using mutate and select

问题描述

library（dplyr）

library(dplyr)

我有以下数据：

d1 <- data_frame(
name = c("jim", "john", "jim", "john"),
`2012` = c(57, 58, 47, 57),
`2013` = c(14, 3, 3, 90))

我想使用mutate函数创建两个新行，以便获得每年的john和jim总计。我希望数据看起来像这样：

I would like to create two new rows using mutate function so that I have the totals for john and jim for each year. I would like the data to look like this:

d1 <- data_frame(
name = c("jim", "john", "jim", "john", "jim total", "john total"),
`2012` = c(57, 58, 47, 57, 104, 115 ),
`2013` = c(14, 3, 3, 90, 17, 93))

我已经尝试了以下其他事情：

I've tried the following amoungst other things:

d1 %>% 
 mutate(jim total = rowSums(select(., contains("jim")))) 

但是我不太明白我想要。有任何想法吗？

But I'm not quite getting what I want. Any ideas?

谢谢

推荐答案

您可以先进行总结，然后再进行总结将它们绑定到原始df，即

You can summarise first and then bind them to your original df, i.e.

library(tidyverse)

bind_rows(d1,
           d1 %>% 
             group_by(name) %>% 
             summarise_all(funs(sum)) %>%
             mutate(name = paste0(name, '_total')))

这给出了

# A tibble: 6 x 3
   name       `2012` `2013`
  <chr>       <dbl>  <dbl>
1 jim            57     14
2 john           58      3
3 jim            47      3
4 john           57     90
5 jim_total     104     17
6 john_total    115     93

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