dplyr取消引用不适用于过滤器功能 [英] dplyr unquoting does not work with filter function
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问题描述
也许我遗漏了一些东西,但是我似乎无法使dplyr的取消报价操作符与过滤器功能一起使用。
示例
set.seed(1234)
A = matrix(rnorm(100),nrow = 10,ncol = 10)
colnames(A)<-paste( var,seq(1 :10),sep =)
varname_test<- var2
A<-as_tibble(A)
select(A,!! varname_test)#这按预期方式工作
#这不只给我var2
#为正
的行(result1<-filter(A,!! ; 0))
#这就是结果1应该看起来像
的样子(result2<-filter(A,var2> 0))
#result1不等于result2
我将不胜感激!
解决方案
我建议以下内容:
库(dplyr)
filter_at(A,vars(starts_with(varname_test)),any_vars(。> 0))
小标题:3 x 10
var1 var2 var3 var4 var5 var6 var7 v ar8 var9 var10
< dbl> < dbl> < dbl> < dbl> < dbl> < dbl> < dbl> < dbl> < dbl> < dbl>
1 -2.35 0.0645 0.460 -0.501 -0.281 -1.01 -0.670 0.648 -0.174 1.00
2 0.429 0.959 -0.694 -1.63 -0.994 -0.162 -0.00760 2.07 0.850 -0.496
3 -0.890 2.42 -0.936 -0.466 -0.497 -1.16 0.336 -0.317 -1.19 2.12
maybe I am missing something, but I can't seem to make dplyr's unquoting operator to work with the filter function. It does with with select, but not with filter...
Example
set.seed(1234)
A = matrix(rnorm(100),nrow = 10, ncol = 10)
colnames(A) <- paste("var", seq(1:10), sep = "")
varname_test <- "var2"
A <- as_tibble(A)
select(A, !!varname_test) #this works as expected
# this does NOT give me only the rows where var2
# is positive
(result1 <- filter(A, !!varname_test > 0))
# This is how the result 1 should look like
(result2 <- filter(A, var2 > 0))
# result1 is not equal to result2
I would appreciate any help!
解决方案
I would suggest the following:
library(dplyr)
filter_at(A, vars(starts_with(varname_test)), any_vars(. > 0))
A tibble: 3 x 10
var1 var2 var3 var4 var5 var6 var7 var8 var9 var10
<dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
1 -2.35 0.0645 0.460 -0.501 -0.281 -1.01 -0.670 0.648 -0.174 1.00
2 0.429 0.959 -0.694 -1.63 -0.994 -0.162 -0.00760 2.07 0.850 -0.496
3 -0.890 2.42 -0.936 -0.466 -0.497 -1.16 0.336 -0.317 -1.19 2.12
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