提取网址来自Drupal 8中链接字段的标题? [英] Extract Url & Title from link field in Drupal 8?
问题描述
我正在尝试检索
I'm trying to retrieve the URL and the Title values of a Link field in Drupal 8.
在我的自定义控制器中,我使用以下命令检索节点: / p>
In my custom controller, I retrieve the nodes with:
$storage = \Drupal::entityManager()->getStorage('node');
$nids = $storage->getQuery()
->condition('type', 'partners')
->condition('status', 1)
->execute();
$partners = $storage->loadMultiple($nids);
当我遍历所有节点以预处理变量时,我会给出自己的看法喜欢检索 URL 和 Title 。
When I loop throught all my nodes, to preprocess vars I'll give to my view, I would like to retrieve the URL and the Title.
foreach ($partners as $key => $partner) {
$variables['partners'][] = array(
'image' => $partner->field_logo->entity->url(),
'url' => $partner->field_link->value, // Can't retrieve values of link field
);
}
不幸的是,我没有找到如何检索 URL 和 field_link 的标题。
Unfortunately, I don't found how to retrieve the URL and the Title of field_link.
感谢您的帮助。
推荐答案
在Twig模板内部的节点级别,您可以使用:
At the node level, inside your Twig template you can use:
{{content.field_link.0 ['#url']}}
& {{content.field_link.0 ['#title']}}
例如:
< a href = {{content.field_link.0 ['#url']}}> {{ content.field_link.0 ['#title']}}< / a>
field_link
是相关链接字段的名称。
field_link
being the name of the link field in question.
这篇关于提取网址来自Drupal 8中链接字段的标题?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!