查找两个unix时间戳之间的日期存在问题 [英] Problems with finding the days between two unix timestamps
问题描述
我已经知道很多问题和答案，但是不幸的是，我认为我的情况可能与众不同？由于某种原因，时间的变化似乎使计算的日期比应该计算的要少一天。
I know there a lot of questions and answers of this already, but unfortunately I think my situation may be unique? For some reason, the time-change seems to be making the day calculate as one day less than it should be calculating.
这是我使用的PHP，它是一直很好，直到开始分别与夏令时之前和夏令时之前的开始和结束日期重叠（仅供参考，这是一个新问题，因为夏令时开始于本周末！）：
Here is my PHP that I was using and it was working great, until it started to overlap a start and end date that was BEFORE daylight savings, and AFTER daylight savings, respectively (FYI, this is a recent issue, since daylight savings time starts this weekend!):
//$lastDate and $firstDate are 2 unix timestamps with valid month, day, and year values.
//The times are irrelevant at this point, they are only meant to represent a day.
//I start by making sure these have the same time values.
$lastDate = mktime(23, 59, 59, date("m", $lastDate), date("j", $lastDate), date("Y", $lastDate));
$firstDate = mktime(23, 59, 59, date("m", $firstDate), date("j", $firstDate), date("Y", $firstDate));
//Then calculate the total number of days in between.
$totalDays = abs(floor(($firstDate - $lastDate)/(60*60*24)));
同样，要清楚一点，如果我不重叠夏令时，上述方法也适用...
So again, to be clear, the above works if i'm not overlapping the daylight savings time change...
供参考：
而且，我现在仍在使用PHP 5.2。
And, I'm still on PHP 5.2 right now.
编辑/更新：
我在此链接上找到了以下内容：
EDIT/UPDATE:
I've found the following on this links:
和
如何计算不用86400除以php的2个unix时间戳之间的时间间隔（60400 * 60 * 24）
//$lastDate and $firstDate are 2 unix timestamps with valid month, day, and year values.
//The times are irrelevant at this point, they are only meant to represent a day.
//I start by making sure these have the same time values.
$lastDate = mktime(10, 00, 00, date("m", $lastDate), date("j", $lastDate), date("Y", $lastDate));
$firstDate = mktime(10, 00, 00, date("m", $firstDate), date("j", $firstDate), date("Y", $firstDate));
//Then calculate the total number of days in between.
$totalDays = floor($firstDate / 86400) - floor($lastDate/ 86400);
对于DST的交叉，它现在似乎可以正常工作。有人看到这个问题吗？
And it seems to work right now for the crossover of DST. Anyone see any issues with this?
推荐答案
您是否在PHP 5.3+上运行？ DateInterval 非常适合这个问题。
http://www.php.net/manual/en/datetime.diff.php
Are you running on PHP 5.3+? A DateInterval fits the problem nicely.
http://www.php.net/manual/en/datetime.diff.php
<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
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