根据过滤器值突出显示单元格内容中字符串的一部分 [英] Highlight part of a string in a cell content based on a filter value

问题描述

作为

解决方案

这有点冗长，但VBA通常来说都是这样：

  library（DT）
 set.seed（1986）
x<-vector（）
＃创建伪造的dna或rna序列（已经有一段时间了因为我使用了bio）
 for（i in 1:10）{
x [i]<-paste0（sample（c（ A， G， T， C） ，10，replace = TRUE），crash =）
} 
 
 dim（x）<-c（5,2）
 
 datatable（x ，options = list（rowCallback = JS（
 function（row，data） {
 data [0] = data [0] .replace（'CC'，'< span style = \ color：red\> CC< / span>'）; 
 data [0] = data [0] .replace（’TT’，’< span style = \ color：blue\> TT< / span>'）; 
 data [0] = data [0] .replace（‘GG’，’< span style = \ color：green\> GG< / span>'）; 
 data [1] = data [1] .replace（'CC'，'< span style = \ color：red\> CC< / span>'）; 
 data [1] = data [1] .replace（’TT’，’< span style = \ color：blue\> TT< / span>'）; 
 data [1] = data [1] .replace（‘GG’，’< span style = \ color：green\> GG< / span>'）; 
 $（’td：eq（0）'，行）.html（data [0]）; 
 $（’td：eq（1）'，行）.html（data [1]）; 
} 
），dom ='t'））
  

As the next step to the example provided in http://rstudio.github.io/DT/010-style.html I wish to highlight a part of a string in a cell based on a filter value as shown in the image below. I am trying to highlight specific motifs in biological sequence data in table format. Given below is the Excel VBA code and a representative image. Is it possible to achieve this in R?

Sub SequencePartColourMacro()
Dim Col, Row, FirstRow, LastRow As Integer, Col As Long

Col = 6
FirstRow = 2
LastRow = ThisWorkbook.Sheets("Sequences").Cells(Rows.Count, "F").End(xlUp).Row

Test1 = "CC"
Test2 = "TT"
Test3 = "GG"

For Row = FirstRow To LastRow
   Sequence = ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Value
   For x = 1 To Len(Sequence)
     SubSequence1 = Mid(Sequence, x, 2)
     If SubSequence1 = Test1 Then
       ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Characters(x, 2).Font.Color = RGB(0, 0, 255)
       ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Characters(x, 2).Font.Bold = True
     End If
    If SubSequence1 = Test2 Then
       ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Characters(x, 2).Font.Color = RGB(0, 102, 0)
       ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Characters(x, 2).Font.Bold = True
    End If
    If SubSequence1 = Test3 Then
       ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Characters(x, 2).Font.Color = RGB(255, 153, 0)
       ThisWorkbook.Sheets("Sequences").Cells(Row, Col).Characters(x, 2).Font.Bold = True
    End If
 Next x
 Next Row
 End Sub

解决方案

This is a little verbose, but so is VBA in general:

library(DT)
set.seed(1986)
x <- vector()
# create fake dna or rna sequence (it's been a while since I took bio)
for (i in 1:10) {
  x[i] <- paste0(sample(c("A","G","T","C"),10,replace=TRUE), collapse="")
}

dim(x) <- c(5,2)

datatable(x, options = list(rowCallback=JS(
  "function(row,data) {
    data[0]=data[0].replace('CC','<span style=\"color:red\">CC</span>');
    data[0]=data[0].replace('TT','<span style=\"color:blue\">TT</span>');
    data[0]=data[0].replace('GG','<span style=\"color:green\">GG</span>');
    data[1]=data[1].replace('CC','<span style=\"color:red\">CC</span>');
    data[1]=data[1].replace('TT','<span style=\"color:blue\">TT</span>');
    data[1]=data[1].replace('GG','<span style=\"color:green\">GG</span>');
    $('td:eq(0)', row).html(data[0]);
    $('td:eq(1)', row).html(data[1]);
  }"
  ), dom = 't'))

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