如何返回许多承诺并在执行其他操作之前等待所有这些承诺 [英] How to return many Promises and wait for them all before doing other stuff
问题描述
我有一个循环,该循环调用异步完成的方法。该循环可以多次调用该方法。在此循环之后,我还有另一个循环,只有在完成所有异步工作后才需要执行。
因此,这说明了我想要的内容:
for(i = 0; i< 5; i ++){
doSomeAsyncStuff();
}
for(i = 0; i< 5; i ++){
doSomeStuffOnlyWhenTheAsyncStuffIsFinish();
}
我对诺言不太熟悉,所以有人可以帮助我实现这一目标吗? p>
这是我的 doSomeAsyncStuff()
的行为:
function doSomeAsyncStuff(){
var editor = generateCKEditor();
editor.on('instanceReady',function(evt){
doSomeStuff();
//应该有我认为的诺言的resolve()。
})
}
也许我必须做这样的事情:
function doSomeAsyncStuff(){
var editor = generateCKEditor();
返回新的Promise(function(resolve,refuse){
editor.on('instanceReady',function(evt){
doSomeStuff();
resolve(true);
});
});
}
但是我不确定语法。
您可以使用 Promise.all
(规范, MDN ):它接受一堆单独的承诺,并给您带来一个单独的承诺,当您所有的承诺都得到解决时
因此,如果您使 doSomeAsyncStuff
返回一个诺言,则:
const promises = [];
// ^^^^^---------------使用`const`或`let`,而不是`var `
for(让i = 0; i< 5; i ++){
// ^^^ -------------------- ---增加了丢失的声明
promises.push(doSomeAsyncStuff());
}
Promise.all(承诺)
.then(()=> {
for(let i = 0; i< 5; i ++) {
// ^^^ -----添加了缺少的声明
doSomeStuffOnlyWhenTheAsyncStuffIsFinish();
}
})
.catch((e)=> {
//在这里处理错误
});
MDN上有关于诺言的文章此处。我还会在我的书 JavaScript:The New Toys 的第8章中详细介绍一些许诺,如果您有兴趣的话,可在我的个人资料中链接。
下面是一个示例:
函数doSomethingAsync(value){
return new Promise((resolve)=> ; {
setTimeout(()=> {
console.log( Resolution + value);
resolve(value);
},Math.floor(Math。 random()* 1000));
});
}
function test(){
const promises = [];
for(let i = 0; i< 5; ++ i){
promises.push(doSomethingAsync(i));
}
Promise.all(应许)
.then((结果)=> {
console.log(全部完成,结果);
})
.catch((e)=> {
//在这里处理错误
});
}
test();
示例输出(由于 Math.random
,首先完成的内容可能会有所不同):
解决3
解决2
解决1
解决4
解决0
全部完成[0,1,2,3,4]
I have a loop which calls a method that does stuff asynchronously. This loop can call the method many times. After this loop, I have another loop that needs to be executed only when all the asynchronous stuff is done.
So this illustrates what I want:
for (i = 0; i < 5; i++) {
doSomeAsyncStuff();
}
for (i = 0; i < 5; i++) {
doSomeStuffOnlyWhenTheAsyncStuffIsFinish();
}
I'm not very familiar with promises, so could anyone help me to achieve this?
This is how my doSomeAsyncStuff()
behaves:
function doSomeAsyncStuff() {
var editor = generateCKEditor();
editor.on('instanceReady', function(evt) {
doSomeStuff();
// There should be the resolve() of the promises I think.
})
}
Maybe I have to do something like this:
function doSomeAsyncStuff() {
var editor = generateCKEditor();
return new Promise(function(resolve,refuse) {
editor.on('instanceReady', function(evt) {
doSomeStuff();
resolve(true);
});
});
}
But I'm not sure of the syntax.
You can use Promise.all
(spec, MDN) for that: It accepts a bunch of individual promises and gives you back a single promise that is resolved when all of the ones you gave it are resolved, or rejected when any of them is rejected.
So if you make doSomeAsyncStuff
return a promise, then:
const promises = [];
// ^^^^^−−−−−−−−−−−−−−−−−−−−−−−−−−− use `const` or `let`, not `var`
for (let i = 0; i < 5; i++) {
// ^^^−−−−−−−−−−−−−−−−−−−−−−−− added missing declaration
promises.push(doSomeAsyncStuff());
}
Promise.all(promises)
.then(() => {
for (let i = 0; i < 5; i++) {
// ^^^−−−−−−−−−−−−−−−− added missing declaration
doSomeStuffOnlyWhenTheAsyncStuffIsFinish();
}
})
.catch((e) => {
// handle errors here
});
MDN has an article on promises here. I also cover promsies in detail in Chapter 8 of my book JavaScript: The New Toys, links in my profile if you're interested.
Here's an example:
function doSomethingAsync(value) {
return new Promise((resolve) => {
setTimeout(() => {
console.log("Resolving " + value);
resolve(value);
}, Math.floor(Math.random() * 1000));
});
}
function test() {
const promises = [];
for (let i = 0; i < 5; ++i) {
promises.push(doSomethingAsync(i));
}
Promise.all(promises)
.then((results) => {
console.log("All done", results);
})
.catch((e) => {
// Handle errors here
});
}
test();
Sample output (because of the Math.random
, what finishes first may vary):
Resolving 3 Resolving 2 Resolving 1 Resolving 4 Resolving 0 All done [0,1,2,3,4]
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