如何基于动态定义的变量解构对象 [英] How to destructure an object based on a dynamic defined variable

问题描述

我正在处理一个不可变的对象，我需要添加一个不可变的对象。

I am working with an immutable object that I need to add subtract an array of values from.

我知道可以使用ES6进行以下破坏。

I know it's possible using ES6 destructing with the following.

const {countries, remainder} = someObj // {countries:...,languages:..., ...keys};

最后，剩下的就是没有国家密钥的新对象。

This will end me up with the remainder being the new Object without the countries key.

因此，我发现可以在数组上使用reduce来从对象中删除所有值，最后使用默认参数返回新对象，即

Therefore I figured out that I could use reduce on an array to go through and remove all the values from the object, returning a new object in the end, using the default parameter, being the original object.

但是，我不确定该如何处理，因为键的名称在数组中定义。

However, I am not sure how to go about it, because the names of keys are defined in the array.

arrayToRemove.reduce((total, value) => {
  const { extractValue: [value], ...remainder } = total
  return remainder;
}, { ...originalObj });

arrayToRemove.reduce((total, value) => {
  const { [extractValue], ...remainder } = total
  return remainder;
}, { ...originalObj });

我期望最终得到一个新的Object，而没有包含在名为arrayToRemove的数组中的键。

I am expecting to end up with a new Object without the keys that are contained in the array called arrayToRemove.

我需要在保持不变性的同时执行此操作，因此我不能仅遍历原始对象并将其从其中删除，因此我认为上述方法是一个聪明的方法。

I need to do this while maintaining immutability, so I cannot just loop through the original object and remove them from it, so I thought the above would be a bright way to go about it.

感谢任何帮助。

推荐答案

您可以使用计算出的属性名称

在此处了解更多信息：对象属性分配模式[YDKJS：ES6&

Read more here: object property assignment pattern [YDKJS: ES6 & Beyond]

var originalObj = { foo: 1, bar: 2, baz: 3, },
    arrayToRemove = ['foo', 'bar'],
    result = arrayToRemove.reduce((total, key) => {
        const { [key]: dummy, ...remainder } = total;
        return remainder;
    }, originalObj);


console.log(result);

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