违反完整性约束:1052列和where子句不明确 [英] Integrity constraint violation: 1052 Column and in where clause is ambiguous
问题描述
我有两个表 Tbl_payroll_leave_employeev2
和 tbl_payroll_leave_schedulev2
,我想加入
他们,但是我收到这样的错误
I have two table the Tbl_payroll_leave_employeev2
and tbl_payroll_leave_schedulev2
and i want to join
them but im getting an error like this
SQLSTATE [23000]:违反完整性约束:1052列'payroll_leave_employee_id'在where子句不明确(SQL:从
tbl_payroll_leave_employee_v2
内部联接中选择payroll_employee_id
内部联接tbl_payroll_leave_schedulev2 $ c
其中tbl_payroll_leave_employee_v2
上的$ c>。payroll_leave_employee_id
=tbl_payroll_leave_schedulev2
。 code> payroll_leave_employee_idpayroll_leave_employee_id
= 5)◀
SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'payroll_leave_employee_id' in where clause is ambiguous (SQL: select
payroll_employee_id
fromtbl_payroll_leave_employee_v2
inner jointbl_payroll_leave_schedulev2
ontbl_payroll_leave_employee_v2
.payroll_leave_employee_id
=tbl_payroll_leave_schedulev2
.payroll_leave_employee_id
wherepayroll_leave_employee_id
= 5) ◀
我的表结构
My table structure
$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id')
->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id')
->where('payroll_leave_employee_id',$emp)
->get();
推荐答案
在这种情况下,必须定义字段<$表 tbl_payroll_leave_employee_v2
或表 tbl_payroll_leave_schedulev2
In where condition, you must define the field payroll_leave_employee_id
of table tbl_payroll_leave_employee_v2
or table tbl_payroll_leave_schedulev2
$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id')
->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id')
->where('tbl_payroll_leave_schedulev2.payroll_leave_employee_id',$emp)
->get();
这篇关于违反完整性约束:1052列和where子句不明确的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!