验证Java中包含非英语（UTF-8）字符的电子邮件地址 [英] validating email address which contains non-english (UTF-8) character in Java

问题描述

我的电子邮件ID为空

闪闪发光@闪闪发光.com 

我需要在服务器端验证此类电子邮件，以便用户无法输入此类电子邮件。.

i有通过使用以下正则表达式解决了JavaScript中的类似问题-

i need to validate this type of email at server side so that user can not enter this type of email..
i have solved similar problem in javascript by using below regex-

/^([a-z0-9\+_\-]+)(\.[a-z0-9\+_\-]+)*@([a-z0-9\-]+\.)+[a-z]{2,6}$/gi

但是。无法在Java中执行相同的操作。请帮助我。

提前谢谢！！！

But. unable to do same thing in java.Please help me guys.
Thanks in advance!!!

推荐答案

Java正则表达式模式（？i）[-a-z0-9 + _] [-a-z0-9 + _。] * @ [-a-z0-9] [-a -z0-9。] * \\。[az] {2,6} 就足够了。模式的含义如下：

The Java regular expression pattern (?i)[-a-z0-9+_][-a-z0-9+_.]*@[-a-z0-9][-a-z0-9.]*\\.[a-z]{2,6} should suffice. Here's what the pattern means:

(?i)            # Case insensitive flag
[-a-z0-9+_]     # First character
[-a-z0-9+_.]*   # Zero or more characters
@               # Literal '@' character
[-a-z0-9]       # Match a single character
[-a-z0-9.]*     # Match zero or more characters
\.              # Literal '.' character
[a-z]{2,6}      # Match 2 through 6 alpha characters

以下测试代码...

final String ps =
        "(?i)[-a-z0-9+_][-a-z0-9+_.]*@[-a-z0-9][-a-z0-9.]*\\.[a-z]{2,6}";
final Pattern p = Pattern.compile(ps);
for (String s : new String[] {"[e-mail]", "[e-mail]",
        "[e-mail]", "[e-mail]", "[e-mail]", "[e-mail]",
        "[e-mail]", "[e-mail]", "[e-mail]", "[e-mail]",
        "闪闪发光@闪闪发光.com"})
{
    final Matcher m = p.matcher(s);
    if (m.matches()) {
        System.out.println("Success: " + s);
    } else {
        System.out.println("Fail: " + s);
    }
}

...将输出：

Success: [e-mail]
Success: [e-mail]
Success: [e-mail]
Success: [e-mail]
Success: [e-mail]
Success: [e-mail]
Success: [e-mail]
Success: [e-mail]
Fail: [e-mail]
Fail: [e-mail]
Fail: 闪闪发光@闪闪发光.com

通过使用 Matcher.matches（）方法，您不需要包含 ^ 行首或 $ 行尾边界匹配结构，因为 Matcher.matches（）将在整个字符串上匹配。

By using the Matcher.matches() method, you don't need to include the ^ start-of-line or $ end-of-line boundary matching constructs since Matcher.matches() will match on the whole string.

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