JavaScript中的XPath属性引用 [英] XPath attribute quoting in JavaScript

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本文介绍了JavaScript中的XPath属性引用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试构建一个将在XPath中正确引用/转义属性的函数。我已经在C#中的这里此处,但我在JavaScript中的实现导致错误此表达式不是合法表达式

I am trying to build a function that will properly quote/escape an attribute in XPath. I have seen solutions posted in C# here and here, but my implementation in JavaScript results in an error "This expression is not a legal expression"

这是我的函数:

function parseXPathAttribute(original){
            let result = null;
            /* If there are no double quotes, wrap in double quotes */
            if(original.indexOf("\"")<0){
                result = "\""+original+"\"";
            }else{
                /* If there are no single quotes, wrap in single quotes */
                if(original.indexOf("'")<0){
                    result = "'"+original+"'";
                }else{ /*Otherwise, we must use concat() */
                    result = original.split("\"")
                    for (let x = 0;x<result.length;x++){
                        result[x] = result[x].replace(/"/g,"\\\"");
                        if (x>0){
                            result[x] = "\\\""+result[x];
                        }
                        result[x] = "\""+result[x]+"\"";
                    }
                    result = result.join();
                    result = "concat("+result+")";
                }

            }

            return result;
        }

样本输入失败:


'hi'

"'hi'"

输出失败的示例:


concat(, \'hi' , \)]

concat("","\"'hi'","\"")]

我不明白为什么这是一个非法表达(假设双引号是转义),所以我不知道该如何解决该功能。

I don't understand why it is an illegal expression (given that the double quotes are escaped), so I don't know how to fix the function.

推荐答案

\ 不是XPath字符串文字中的转义字符(如果是,则可以反斜杠转义其中一个)引号,而不必担心 concat !) \ 本身就是一个完整的字符串,然后是'hi ... ,这没有任何意义。

\ is not an escape character in XPath string literals. (If it was, you could just backslash-escape one of the quotes, and never have to worry about concat!) "\" is a complete string in itself, which is then followed by 'hi..., which doesn't make sense.

所以应该没有反斜杠在您的输出中,应该类似于:

So there should be no backslashes in your output, it should look something like:

concat('"', "'hi'", '"')

我建议:

function xpathStringLiteral(s) {
    if (s.indexOf('"')===-1)
        return '"'+s+'"';
    if (s.indexOf("'")===-1)
        return "'"+s+"'";
    return 'concat("'+s.replace(/"/g, '",\'"\',"')+'")';
}

效率不如预期(其中包括前导/如果第一个/最后一个字符是双引号,则在空字符串段的末尾尾随空格),但这不太重要。

It's not quite as efficient as it might be (it'll include leading/trailing empty string segments if the first/last character is a double-quote), but that's unlikely to matter.

(您真的是说 let 呢?这是非标准的Mozilla专用语言功能;通常会使用 var 。)

(Do you really mean let in the above? This is a non-standard Mozilla-only langauge feature; one would typically use var.)

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