带有对象引用的JPA复合键 [英] JPA Composite Key with Object references
问题描述
在创建带有对象引用的JPA复合密钥时,我遇到了一些问题。实体如下所示,
I have faced some issue while creating JPA Composite Key with Object references. Entities are as show in bellow,
1)我想从Workflow实体中删除 ID 字段,并结合使用 > seqNo 字段和 template (对象引用)字段
1) I wan to remove the ID field from Workflow entity and make a composite key with combining seqNo field and template (object reference) field
2)根据该更改,将现有关系更新为命令实体(@JoinColumn(名称= WORKFLOW_ID,referencedColumnName = ID))
2) According to that change updated the existing relationship with Command entity (@JoinColumn(name = "WORKFLOW_ID", referencedColumnName = "ID"))
谢谢。
模板实体:
@Entity
@Table(name = "template")
public class Template implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE)
@SequenceGenerator(name="template_se", sequenceName="TEMPLATE_SE", allocationSize=1, initialValue=1)
@Basic(optional = false)
@Column(name = "ID")
private Integer id;
@Basic(optional = false)
@Column(name = "NAME", unique = true)
private String name;
@OneToMany(cascade = CascadeType.REMOVE, mappedBy = "template")
@LazyCollection(LazyCollectionOption.FALSE)
private List<Workflow> workflowList;
}
工作流程实体:
@Entity
@Table(name = "workflow")
public class Workflow implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE)
@SequenceGenerator(name="wf_se", sequenceName="WF_SE", allocationSize=1, initialValue=1)
@Basic(optional = false)
@Column(name = "ID")
private Integer id;
@Basic(optional = false)
@Column(name = "SEQ_NO")
private int seqNo;
@JoinColumn(name = "T_ID", referencedColumnName = "ID", nullable = false)
@ManyToOne
private Template template;
@Basic(optional = false)
@Column(name = "NAME")
private String name;
}
命令实体:
@Entity
@Table(name = "command")
public class Command implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE)
@SequenceGenerator(name="command_se", sequenceName="COMMAND_SE", allocationSize=1, initialValue=1)
@Basic(optional = false)
@Column(name = "ID")
private Integer id;
@JoinColumn(name = "WORKFLOW_ID", referencedColumnName = "ID")
@ManyToOne(optional = false)
private Workflow workflow;
}
推荐答案
我已经把事情做好了
EmbeddedId类
@Embeddable
public class WorkflowPK implements Serializable {
@Basic(optional = false)
@Column(name = "SEQ_NO")
private int seqNo;
@JoinColumn(name = "T_ID", referencedColumnName = "ID", nullable = false)
@ManyToOne
private Template template;
}
工作流实体(带有EmbeddedId)
Workflow Entity (with EmbeddedId)
@Entity
@Table(name = "workflow")
public class Workflow implements Serializable {
@EmbeddedId
private WorkflowPK id;
@Basic(optional = false)
@Column(name = "NAME")
private String name;
}
模板实体具有双向关系
@Entity
@Table(name = "template")
public class Template implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE)
@SequenceGenerator(name="template_se", sequenceName="TEMPLATE_SE", allocationSize=1, initialValue=1)
@Basic(optional = false)
@Column(name = "ID")
private Integer id;
@Basic(optional = false)
@Column(name = "NAME", unique = true)
private String name;
// Refer the filed "template" inside the Composite key of Workflow entity
@OneToMany(cascade = CascadeType.REMOVE, mappedBy = "id.template")
@LazyCollection(LazyCollectionOption.FALSE)
@OrderBy(value = "id.stepSeqNo")
private List<Workflow> workflowList;
}
命令实体,其中JoinColumn参考
Command entity with JoinColumn reference
@Entity
@Table(name = "command")
public class Command implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE)
@SequenceGenerator(name="command_se", sequenceName="COMMAND_SE", allocationSize=1, initialValue=1)
@Basic(optional = false)
@Column(name = "ID")
private Integer id;
// Refer the Composite key of Workflow entity
@ManyToOne(optional = false)
@JoinColumns ({
@JoinColumn(name="WORKFLOW_SEQ_NO_ID", referencedColumnName = "SEQ_NO"),
@JoinColumn(name="WORKFLOW_T_ID", referencedColumnName = "T_ID"),
})
private WorkflowStep workflow;
}
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