改进2个同步呼叫错误处理以解决4xx错误 [英] Retrofit 2 synchronous call error handling for 4xx Errors

问题描述

我正在使用android-priority-jobqueue，并且我使用改造来对我的rest api进行同步调用，但是我不确定如何处理诸如401未经授权的错误之类的错误，我会向json发送回去说明错误。进行异步呼叫时很简单，但我正在为工作经理调整我的应用程序。以下是IO异常的简单尝试，但是401的422等等？

I'm using a android-priority-jobqueue and I use retrofit to make synchronous calls to my rest api but i'm unsure how to handle errors like 401 Unauthorized errors which I send back json stating the error. Simple when doing async calls but I'm adapting my app for job manager. below is a simple try catch for IO exceptions, but 401's 422's etc? How to do this?

try {
    PostService postService = ServiceGenerator.createService(PostService.class);
    final Call<Post> call = postService.addPost(post);
    Post newPost = call.execute().body();

    // omitted code here

} catch (IOException e) {
    // handle error
}

编辑

对我来说，改型响应对象的使用至关重要改造响应对象允许我

The use of the retrofit response object was the clincher for me, returning the retrofit response object allowed me to

Response<Post> response = call.execute();

if (response.isSuccessful()) {
    // request successful (status code 200, 201)
    Post result = response.body();

    // publish the post added event
    EventBus.getDefault().post(new PostAddedEvent(result));
} else {
    // request not successful (like 400,401,403 etc and 5xx)
    renderApiError(response);
}

推荐答案

检查响应代码并显示适当的消息。

Check response code and show the appropriate message.

尝试一下：

 PostService postService = ServiceGenerator.createService(PostService.class);
 final Call<Post> call = postService.addPost(post);

Response<Post> newPostResponse = call.execute();

// Here call newPostResponse.code() to get response code
int statusCode = newPostResponse.code();
if(statusCode == 200)
    Post newPost = newPostResponse.body();
else if(statusCode == 401)
    // Do some thing... 

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