替换PHP中所有出现在引号内的char [英] Replace all occurences of char inside quotes on PHP

问题描述

我该如何转换这样的内容：

How could I convert something like this:

"hi (text here) and (other text)" come (again)

到此：

"hi \(text here\) and \(other text\)" come (again)

基本上，我想仅转义引号内的括号。

Basically, I want to escape "only" the parentheses that are inside quotes.

编辑

我是Regex的新用户，因此，我尝试了以下操作：

I'm to new in Regex and so, I tried this:

$params = preg_replace('/(\'[^\(]*)[\(]+/', '$1\\\($2', $string);

但这只会逃避第一次出现（。

But this will just escape the first occurrence of (.

编辑2

也许我应该提一下，我的字符串可能已经转义了这些括号，在这种情况下，我不想

Maybe I should mention that my string could have these parentheses already escaped and, in this case, I don't want to escaped them again.

顺便说一句，我需要它同时适用于双引号和单引号，但是我认为只要有一个可行的例子，我就可以做到这一点。其中之一。

By the way, I need it working for both double and single quotes but I think that I can do that as long as I have a working example for one of them.

推荐答案

对于单引号和双引号，都应该这样做：

This should do it for both single and double quotes:

$str = '"hi \(text here)" and (other text) come \'(again)\'';

$str = preg_replace_callback('`("|\').*?\1`', function ($matches) {
    return preg_replace('`(?<!\\\)[()]`', '\\\$0', $matches[0]);
}, $str);

echo $str;

输出

"hi \(text here\)" and (other text) come '\(again\)'

它用于PHP> = 5.3。如果您的版本较低（> = 5），则必须用单独的函数替换回调函数中的匿名函数。

It is for PHP >= 5.3. If you have a lower version (>=5) you have to replace the anonymous function in the callback with a separate function.

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