在Python字符串中的括号前转义（插入反斜杠） [英] Escape (Insert backslash) before brackets in a Python string

问题描述

我需要格式化许多包含相似结构的字符串：

I need to format many strings that contain a similar structure:

 u'LastName FirstName (Department / Subdepartment)'

我的愿望是使字符串看起来像这样：

My wish is to get the string to look like this:

 u'LastName FirstName \(Department / Subdepartment\)'

意思是我需要在左括号和右括号中添加反斜杠。

Meaning I need to add a backslash to the opening bracket and to the closing bracket.

到目前为止，我是在Python中执行此操作：

So far I am doing this in Python:

  displayName = displayName.replace('(', '\(').replace(')', '\)').

哪个似乎还可以，但我只是想知道：

Which seems OK, but I am just wondering:

有没有更Python化的方法？

Is there is a more Pythonic way to do it?

我没有找到正确的方法 Python的String文档，但也许我在错误的地方查找了...

I did not find a proper way Python's String documentation, but maybe I am looking in the wrong place...

推荐答案

您已经找到了最Python化的方法， regex 提供了一种不太可读的解决方案：

You've already found the most Pythonic way, regex provides a not so readable solution:

>>> import re
>>> s = u'LastName FirstName (Department / Subdepartment)'
>>> print re.sub(r'([()])', r'\\\1', s)
LastName FirstName \(Department / Subdepartment\)

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