如何在路径中转义百分比符号（批处理脚本） [英] How to escape percent symbol in path (batch script)

问题描述

这是我的脚本。我尝试了很多方法，但是无法逃脱％符号。

This is my script. I tried many ways, but can't escape % symbol.

@ECHO off
SETLOCAL DisableDELAYEDEXPANSION
CHCP 65001 >NUL

:start
set Input="C:\Transcode\ABC! code's 30% Special"
set Output="C:\Batch Script\DST&2"

REM set /p Input="Enter source folder link: "
REM set /p Output="Enter destination folder link: "  

set "SRC=%Input:"=%"
set "DST=%Output:"=%"

FOR /F "delims=" %%a IN ('DIR /b /s /a-d "%SRC%"') DO (
    call :mklink "%%a" "%%~na" "%%~xa" "%DST%"
)
Goto :EOF

   :mklink
    Set "FILENAME=%~2"
    Set "FILENAME=%FILENAME: =_%"
    Set "FILENAME=%FILENAME:-=_%"
    for %%b in ("%FILENAME:_=" "%") do (
        Echo %%b | FindStr /IRC:"wjpg" >Nul && (
            IF exist "%~4\ABC\%%~b%~3" del "%~4\ABC\%%~b%~3"
            ECHO mklink "%~4\ABC\%%~b%~3" "%~1" >> "%~4\log.txt" 2>&1
            mklink "%~4\ABC\%%~b%~3" "%~1"
        )
    )
    Goto :EOF

注意：路径不能更改（不添加或删除字符）

Attention: path can not change (don't add or remove character)

推荐答案

在常规Windows批处理文件中，可以使用以下两个来对字符串中的％进行转义：

In a regular Windows batch file, you can escape a % in a string by using two of them:

set "Input=C:\Transcode\ABC! code's 30%% Special"

如果需要双引号作为字符串的一部分，则在包含双引号时引用变量：％Input％ 。

If you need double quotes as part of the string, then include them when referencing the variable: "%Input%".

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