Symfony2-将当前登录的用户注入到侦听器中 [英] Symfony2 - Inject the currently logged in user into a listener
问题描述
我正在尝试将当前登录的用户注入到侦听器中.我的目标是每次用户执行任何操作时都将当前\ DateTime()写入我的'demo_user'表的'last_active'列(这两个
I am trying to inject the currently logged in user into a Listener. My goal is to write a current \DateTime() to the 'last_active' column of my 'demo_user' table every time the user does any action (both of this this methods do not work for me) .
app/config/config.yml
# ...
services:
demo.listener:
class: Demo\UserBundle\EventListener\ActivityWatcher.php
arguments: ['@service_container']
tags:
- { name: doctrine.event_listener, event: postLoad }
src/Demo/UserBundle/EventListener/ActivityWatcher.php
namespace Demo\UserBundle\EventListener;
use Doctrine\ORM\Event\LifecycleEventArgs;
use Symfony\Component\DependencyInjection\ContainerInterface;
use Demo\UserBundle\Entity\DemoUser;
class ActivityWatcher
{
protected $container;
public function __construct(ContainerInterface $container)
{
$this->container = $container;
}
public function postLoad(LifecycleEventArgs $args)
{
$entity = $args->getEntity();
$entityManager = $args->getEntityManager();
if ($entity instanceof DemoUser) {
$token = $this->container->get('security.context')->getToken();
$user = $token->getUser();
if($entity->getId() == $user->getId()) {
$entity->setLastActivity( new \DateTime() );
$entityManager->persist($entity);
$entityManager->flush();
}
}
}
}
但是$ token总是空的... 更新:没有提到,发生这种情况时我已经登录并通过了身份验证
But the $token is always empty... UPDATE: Didn't mention, that I'm logged in and authenticated when this happens
FatalErrorException: Error: Call to a member function getUser()
on a non-object ...
有什么想法吗?嗯,谢谢,扬
Any ideas? Arrgh, thanks, Jan
更新:
我也只尝试注入security.context:
I also tried only to inject the security.context:
arguments: ["@security.context"]
但是得到了
ServiceCircularReferenceException: Circular reference detected for "doctrine.orm.default_entity_manager", path: "doctrine.orm.default_entity_manager -> doctrine.dbal.default_connection -> wwk.listener -> security.context -> security.authentication.manager -> security.user.provider.concrete.administrators".
推荐答案
对于symfony 2.4
,您应该可以插入表达式,
所以不是@service_container
使用
@=service('security.context').getToken().getUser()
直接吸引用户
for symfony 2.4
you should be able to inject expression,
so instead of @service_container
use
@=service('security.context').getToken().getUser()
to get user directly
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