快速的二传手导致exc_bad_access [英] swift setter causing exc_bad_access
问题描述
我在下面有一个简单的课程
I have a simple class below
import Foundation
public class UsefulClass: NSObject{
var test:NSNumber{
get{return self.test}
set{
println(newValue)
self.test = newValue
}
}
override init() {
super.init()
self.test = 5;
}
}
我在这里初始化它
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
var testClass = UsefulClass()
}
}
但是它会导致xcode打印出200 5s,然后由于EXC_BAD_ACCESS code = 2而崩溃.为什么会发生这种情况?
But it results in xcode printing out 200 5s and then crashing due to EXC_BAD_ACCESS code = 2. Why does this happen?
推荐答案
@vadian在他的回答中提供了一个解决方案,它可以解决您的问题.让我解释一下发生了什么.
@vadian has provided a solution in his answer, which should fix your problem. Let me just explain what's happening.
您已经创建了一个计算属性,即一个没有变量支持的属性,取而代之的是,getter和setter都通常在另一个存储的属性上进行一些处理,以便分别返回一个值并设置一个新值
You have created a computed property, i.e. a property which is not backed by a variable, instead both the getter and the setter do some processing, usually on another stored property, in order to respectively return a value and set a new value.
这是您计算出的属性:
var test: NSNumber {
get { return self.test }
set {
println(newValue)
self.test = newValue
}
}
看看getter的实现:
Look at the getter implementation:
return self.test
它是做什么的?它读取当前实例的test
属性,并返回它. test
属性是哪个?就是这个:
What does it do? It reads the test
property of the current instance, and returns it. Which is the test
property? It's this one:
var test: NSNumber {
get { return self.test }
set {
println(newValue)
self.test = newValue
}
}
是的,它是相同的属性.您的getter所做的就是递归和无限期地自我调用,直到在运行时发生崩溃为止.
Yes, it's the same property. What your getter does is to recursively and indefinitely calling itself, until a crash happen at runtime.
相同的规则适用于二传手:
The same rule applies to the setter:
self.test = newValue
它会不断调用自身,直到应用程序崩溃为止.
it keeps invoking itself, until the app crashes.
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