删除每隔一行 [英] Delete every other row
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问题描述
我想编写一个循环,该循环删除工作表中的所有行以清理文件.因此,如果我有第1至10行,我想删除第1、3、5、7、9行.
I want to write a loop that deletes entire rows in a sheet to clean-up the file. So if I have row 1 to 10, I want to delete row 1, 3, 5, 7, 9.
Sub deleteeveryotherrow()
For x = 1 To 10
Rows("x:x").Select
Selection.Delete Shift:=xlUp
x = x + 2
Next x
End Sub
推荐答案
"x:x"
只是一个文字字符串,因此无法按预期工作.
"x:x"
is just a literal string, so will not work as you expect.
改为使用Rows(x & ":" & x).Select
.
您还应该考虑将循环从10倒向1:
You should also consider running the loop backwards from 10 to 1:
For x = 9 To 1 Step -2
否则,您的索引将被弄乱.然后,您将可以删除x = x + 2
行.
otherwise you'll get your indexing tangled up. You'll then be able to remove the line x = x + 2
.
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