如何获取在Python中捕获的异常的名称? [英] How to get the name of an exception that was caught in Python?

问题描述

如何获取Python中引发的异常的名称?

How can I get the name of an exception that was raised in Python?

例如

try:
    foo = bar
except Exception as exception:
    name_of_exception = ???
    assert name_of_exception == 'NameError'
    print "Failed with exception [%s]" % name_of_exception

例如，我正在捕获多个(或所有)异常，并希望在错误消息中打印异常的名称.

For example, I am catching multiple (or all) exceptions, and want to print the name of the exception in an error message.

推荐答案

以下是获取异常类名称的几种不同方法:

Here are a few different ways to get the name of the class of the exception:

1. type(exception).__name__
2. exception.__class__.__name__
3. exception.__class__.__qualname__

1. type(exception).__name__
2. exception.__class__.__name__
3. exception.__class__.__qualname__

例如

try:
    foo = bar
except Exception as exception:
    assert type(exception).__name__ == 'NameError'
    assert exception.__class__.__name__ == 'NameError'
    assert exception.__class__.__qualname__ == 'NameError'

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