通过php exec函数传递$ _SERVER数组 [英] pass $_SERVER array through php exec function

问题描述

可能重复:
安全执行的shell脚本；在执行前转义vars

Possible Duplicate:
Safe executing shell scripts; escaping vars before execution

我想通过php exec()函数传递$_SERVER数据，以便为后台进程运行另一个脚本.
传递一个简单的参数，我这样做是这样的:

I want to pass $_SERVER data through php exec() function to run another script for background process.
to pass a simple parameter I do it like this:

exec("/usr/bin/php -f bg.php parameter1 > /dev/null &");

但是我认为不可能直接将数组传递给该函数.所以我尝试了 serialize($_SERVER) .但是现在有一个更大的问题.诸如引号，分号之类的字符会破坏shell命令，因此无法正常工作.

But I think it is impossible to directly pass an array to this function. So I tried serialize($_SERVER) . but now there's a bigger problem. Characters like quotations, semicolons and many others break down the shell command and it doesn't work properly.

那么解决这个问题的解决方案是什么?

So what's the solution to solve this problem?

推荐答案

也许您正在寻找的是: http://php.net/manual/en/function.escapeshellarg.php

Maybe what you are looking for is: http://php.net/manual/en/function.escapeshellarg.php

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