php-在处爆炸字符串.但忽略小数，例如2.9 [英] php - explode string at . but ignore decimal eg 2.9

问题描述

目前，我正在.处分解一个字符串，它可以按我的喜好工作.唯一的问题是，当.作为小数点出现时也会爆炸.有没有一种方法可以将decimal点排除在爆炸功能之外?

Currently I am exploding a string at . and it works as I like. the only issue is that is also explodes when the . occurs as a decimal point. Is there a way of excluding decimal points from the explode function?

我当前的设置: 如您所见，它在两个数字之间的.处爆炸

My current setup: As you can see it is exploding at . between the two numbers

$String = "This is a string.It will split at the previous point and the next one.Here 7.9 is a number";

$NewString = explode('.', $String);

print_r($NewString);

output

Array ( 
[0] => This is a string 
[1] => It will split at the previous point and the next one 
[2] => Here 7 
[3] => 9 is a number 
)

推荐答案

您可以使用 preg_split 为此，使用/(?<!\d)\.(?!\d)/的正则表达式:

You can use preg_split for this with the regex of /(?<!\d)\.(?!\d)/:

<?php
    $String = "This is a string. It will split at the previous point and the next one. Here 7.9 is a number";

    $NewString = preg_split('/(?<!\d)\.(?!\d)/', $String);

    print_r($NewString);
?>

输出:

Array
(
    [0] => This is a string
    [1] =>  It will split at the previous point and the next one
    [2] =>  Here 7.9 is a number
)

> 演示

正则表达式是什么意思?

• (?<!\d)-负向后看"，表示只有在点前没有数字(\d)时，它才会匹配
• \.-文字.字符.它需要转义，因为正则表达式中的.表示任何字符"
• (?!\d)-负向超前"，表示仅在点后没有数字(\d)时才匹配

• (?<!\d) - a "negative lookbehind" meaning it will only match if there is NO digit (\d) before the dot
• \. - a literal . character. It needs to be escaped as . in regex means "any character"
• (?!\d) - a "negative lookahead" meaning it will only match if there is NO digit (\d) after the dot

其他:

您可以通过使用正则表达式(/(?<!\d)\.(?!\d)\s*/)来消除空格，该正则表达式也将与点后的任意数量的空格匹配，或者可以使用$NewString = array_map('trim', $NewString);.

You can get rid of the spaces by using a regex as /(?<!\d)\.(?!\d)\s*/ that will also match any number of white-spaces after the dot, or alternatively you can use $NewString = array_map('trim', $NewString);.

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