PHP爆炸和Get_Url:未显示URL [英] PHP Explode and Get_Url: Not Showing up the URL

问题描述

有点难以理解.

在header.php中，我有以下代码:

in the header.php i have this code:

<?
$ID = $link;
$url = downloadLink($ID);
?>

我通过此变量$ link获得ID-> 12345678 并通过$ url获得来自functions.php的完整链接

I get the ID with this Variable $link --> 12345678 and with $url i get the full link from the functions.php

在functions.php中，我有此代码段

in the functions.php i have this snippet

function downloadlink ($d_id)
  {
    $res = @get_url ('' . 'http://www.example.com/' . $d_id . '/go.html');
    $re = explode ('<iframe', $res);
    $re = explode ('src="', $re[1]);
    $re = explode ('"', $re[1]);
    $url = $re[0];
    return $url;
  } 

，通常它会打印出网址..但是，我听不懂代码.

and normally it prints the url out.. but, i cant understand the code..

推荐答案

它是用一种奇怪的方式编写的，但基本上downloadLink()的作用是这样的:

It's written in kind of a strange way, but basically what downloadLink() does is this:

1. 从http://www.example.com/<ID>/go.html
下载HTML
2. 获取HTML，并在出现字符串<iframe的每个点处将其拆分.
3. 现在，获取HTML中 first <iframe之后的所有内容，并在出现字符串src="的每个点处将其拆分.
4. 现在将第一个src="之后的所有内容拿走，并在出现"的每个点处将其拆分.
5. 返回第一个"之前的之前的内容.

1. Download the HTML from http://www.example.com/<ID>/go.html
2. Take the HTML, and split it at every point where the string <iframe occurs.
3. Now take everything that came after the first <iframe in the HTML, and split it at every point where the string src=" appears.
4. Now take everything after the first src=" and split it at every point where " appears.
5. Return whatever was before the first ".

因此，这是一种很差的方法，但是有效地它会在HTML代码中寻找这种情况的首次出现:

So it's a pretty poor way of doing it, but effectively it looks for the first occurence of this in the HTML code:

<iframe src="<something>"

并返回<something>.

一种不同的方法，根据注释的要求:

确实没有任何特定的正确"方法可以执行此操作，但是一种相当简单的方法是将其更改为:

There's not really any particular "right" way to do it, but a fairly straightforward way would be to change it to this:

function downloadlink ($d_id)
{
    $html = @get_url ('' . 'http://www.example.com/' . $d_id . '/go.html');
    preg_match('/\<iframe src="(.+?)"/', $html, $matches);
    return $matches[1];
}

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