从JSON文件中删除JSON对象 [英] Removing JSON object from JSON file
本文介绍了从JSON文件中删除JSON对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试编写一个从json文件中删除对象的函数. json文件使用一系列用户格式进行格式化:
I am trying to write a function that removes an object from a json file. The json file is formatted with an array of users as such:
{
"users": [
{
"username": "test1",
"answers": [
"Red",
"Blue",
"Yellow",
"Green"
]
},
{
"username": "test2",
"answers": [
"1",
"2",
"3",
"4"
]
}
]
}
由于某些原因,我编写的代码无法正常工作.我希望能够仅将一个变量"test2"传递给函数,然后将该特定用户从对象中删除,包括他们的答案.
The code I wrote is not working for some reason. I want to be able to just pass a variable "test2" into the function and then have that particular user removed from the object, including their answers.
var removeUser = user;
var data = fs.readFileSync('results.json');
var json = JSON.parse(data);
var users = json.users;
delete users.users[user];
fs.writeFileSync('results.json', JSON.stringify(json, null, 2));
推荐答案
您可以使用filter
删除不需要的用户
You can use filter
to remove the user you do not want
var fs = require('fs');
var removeUser = "test2";
var data = fs.readFileSync('results.json');
var json = JSON.parse(data);
var users = json.users;
json.users = users.filter((user) => { return user.username !== removeUser });
fs.writeFileSync('results.json', JSON.stringify(json, null, 2));
这篇关于从JSON文件中删除JSON对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文