F#Seq.sortBy降序排列 [英] F# Seq.sortBy in descending order

问题描述

我对F#还是很陌生，它来自Seq.sortBy函数，但是它以升序对列表进行排序.如何使用Seq.sort对其进行降序排序?

I am fairly new to F# and came by the Seq.sortBy function however it is sorting my list in ascending order. How do I get it to sort in descending order using the Seq.sort?

例如，示例代码为...

For instance an example code would be...

let DisplayList =
seq{0..10}
|> Seq.sortBy(fun x -> x)
|> Seq.iter(fun x -> Console.WriteLine(x.ToString()))

当我真的希望它从10变为1时，输出为1 2 3 4 5 6 7 8 9 10.

gives me an output of 1 2 3 4 5 6 7 8 9 10, when I really want it to do it from 10 to 1.

推荐答案

请注意其他答案，请注意一元减号和MININT:

Looking at the other answers, beware unary minus and MININT:

let a = [| 1; -1; System.Int32.MinValue; 0; System.Int32.MaxValue; 1 |]

printfn "%A" (a |> Array.sortBy (fun x -> x))
// [|-2147483648; -1; 0; 1; 1; 2147483647|]

printfn "%A" (a |> Array.sortBy (fun x -> -x))  // uh-oh!
// [|-2147483648; 2147483647; 1; 1; 0; -1|]

我认为您实际上想要的是负x减一:

I think you actually want negative-x-minus-one:

printfn "%A" (a |> Array.sortBy (fun x -> -x - 1))
// [|2147483647; 1; 1; 0; -1; -2147483648|]

表示跨越-2^N..2^N-1的环绕整数类型.

for a wraparound integer type that spans -2^N..2^N-1.

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