传递seq< float选项>从F#到RProvider [英] Passing a seq<float option> from F# to RProvider

问题描述

我希望能够将option float的序列传递给F#中的RProvider.如果我有一个带有Some float和None的浮点数序列，如何使用RProvider将None值放入R?我本来希望None等同于R中的NA值，但我无法将seq<option float>传递给R.

I want to be able to pass a sequence of option float to the RProvider in F#. If I have a sequence of floats with Some float and None, how can I get the None values into R with the RProvider? I would have expected the Nones would be equivalent to an NA value in R, but I can't get pass a seq<option float> to R.

例如，使用

open System
open RDotNet
open RProvider
open RProvider.graphics
open RProvider.stats  

let optData4 = 
    seq [Some 10.0; Some 9.0; Some 8.0; None; Some 6.0; 
        Some 5.0; Some 5.0; None; Some 4.0; Some 2.0; 
        None]

let testData4 = 
    namedParams [
        "regPrice", optData4;]
    |> R.data_frame

我遇到多行错误:

System.Exception: No converter registered for type Microsoft.FSharp.Collections.FSharpList`1[[Microsoft.FSharp.Core.FSharpOption`1[[System.Double, mscorlib, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089]], FSharp.Core, Version=4.4.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a]] or any of its base types
>    at [e-mail](String message) in C:\Tomas\Public\bmc\FSharp.RProvider\src\RProvider\RInterop.fs:line 164
   at RProvider.RInteropInternal.REngine.SetValue(REngine this, Object value, FSharpOption`1 symbolName) in C:\Tomas\Public\bmc\FSharp.RProvider\src\RProvider\RInterop.fs:line 274
   at RProvider.RInteropInternal.toR(Object value) in C:\Tomas\Public\bmc\FSharp.RProvider\src\RProvider\RInterop.fs:line 287
   at RProvider.RInterop.passArg@447(List`1 tempSymbols, Object arg) in C:\Tomas\Public\bmc\FSharp.RProvider\src\RProvider\RInterop.fs:line 461
   at [e-mail](IEnumerable`1& next) in C:\Tomas\Public\bmc\FSharp.RProvider\src\RProvider\RInterop.fs:line 469
   at Microsoft.FSharp.Core.CompilerServices.GeneratedSequenceBase`1.MoveNextImpl()
   at Microsoft.FSharp.Core.CompilerServices.GeneratedSequenceBase`1.System-Collections-IEnumerator-MoveNext()
   at System.Collections.Generic.List`1..ctor(IEnumerable`1 collection)
   at Microsoft.FSharp.Collections.SeqModule.ToArray[T](IEnumerable`1 source)
   at RProvider.RInterop.callFunc(String packageName, String funcName, IEnumerable`1 argsByName, Object[] varArgs) in C:\Tomas\Public\bmc\FSharp.RProvider\src\RProvider\RInterop.fs:line 466
   at <StartupCode$FSI_0012>.$FSI_0012.main@() in C:\Users\sranney\repositories\carolina_refit_bits\refit_bits\refit_bits\RDemo.fs:line 102
Stopped due to error

将任何内容传递给RProvider的唯一方法是使用

The only way I can pass anything to the RProvider is if I convert the seq<option float> to a seq<float> with

let optData4 = 
    seq [Some 10.0; Some 9.0; Some 8.0; None; Some 6.0; 
        Some 5.0; Some 5.0; None; Some 4.0; Some 2.0; 
        None]
    |> Seq.choose id

let testData4 = 
    namedParams [
        "regPrice", optData4;]
    |> R.data_frame

但是这否定了无"选项的目的(我认为这与R的NA值相当.

but this negates the purpose of having the option of None (which, I would have thought would be comparable to Rs NA value.

如何将值序列传递给RProvider，其中某些值在F#中为None，而在R中应为NA?

How can I pass a sequence of values to the RProvider where some of the values are None in F# and should be NA in R?

推荐答案

我认为您只需用nan替换None值就能做到这一点(这并不完全正确，因为在R 和NaN是不同的，但是无法表达F#中的浮点数的两个不同的非值):

I think you should be able to do this just be replacing the None values with nan (this is not entirely right, because in R NA and NaN are different, but there is no way to express two different non-values for a float in F#):

let optData4 = 
    [ 10.0; 9.0; 8.0; nan; 6.0; 5.0; 5.0; nan; 4.0; 2.0; nan ]

let testData4 = 
    namedParams [
        "regPrice", optData4;]
    |> R.data_frame

我还没有测试过，但是我认为这是我们内部在Deedle中所做的.

I have not tested this, but I think this is what we do in Deedle internally.

这篇关于传递seq< float选项>从F#到RProvider的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！