F#转发管道以将int转换为bigint [英] F# forward pipe to convert from int to bigint

问题描述

我对F#相当陌生，并且遇到了这种情况，希望有人能解释为什么我的编译器不喜欢该代码...

I am fairly new to F# and came up across this scenario and was hoping someone could explain why my compiler doesnt like the code...

如果在F#中执行以下操作...

If in F# I do the following...

let FloatToInt = 10.0 |> int
let IntToFloat = 10 |> float

一切都很好，并将数字强制转换为相关的数据类型...

Everything is fine and the number is cast to the relevant data type...

但是，如果我执行以下操作...

if however I do the following...

let IntToBigInt = 10 |> bigint

我收到一个错误类型名称或对象构造函数的无效使用". 我认为这是因为bigint的正向管道没有运算符重载吗?

I get a error "Invalid use of type name or object constructor." I assume that this is because there isnt an operator overload for the forward pipe for bigint?

如果我想使此代码成为可能，该怎么办?我知道我可以使用其他语法，例如...

If I wanted to make this code possible, how would I do it? I know I could use different syntax like...

let IntToBigInt = bigint(10)

但是我真的很喜欢Forward Pipe语法，想知道我是否可以实现它，以便...

But I really like the Forward Pipe syntax and would like to know if I can achieve it so that...

let IntToBigInt = 10 |> bigint

会工作...

推荐答案

它与重载无关. 10.0 |> int之所以有效，是因为有一个名为int的函数.但是，没有名为bigint的函数，因此10 |> bigint不起作用.

It has nothing to do with overloads. 10.0 |> int works because there is a function named int. There is however no function named bigint, so 10 |> bigint does not work.

如果您定义一个，它将起作用:

If you define one, it works:

> let bigint (x:int) = bigint(x);; // looks recursive, but isn't
val bigint : int -> System.Numerics.BigInteger

> 42 |> bigint;;
val it : System.Numerics.BigInteger = 42I

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