如何呈现< h:outputLink>的自定义属性? [英] How to render a custom attribute of <h:outputLink>?

问题描述

我正在尝试使用如下代码段来实现pinterest的pinit按钮:

I am trying to implement pinterest's pinit button using a snippet like the one below:

<h:outputLink value="http://pinterest.com/pin/create/button/" class="pin-it-button" count-layout="horizontal">
   <f:param name="url" value="#{beanOne.someMethod}/sometext{prettyContext.requestURL.toURL()}"/>
   <f:param name="media" value="#{beanOne.someOtherMethod}/sometext/somemoretext/#{beanTwo.someMethodTwo}-some-text.jpg"/>
   <f:param name="description" value="#{beanTwo.someOtherMethodTwo}"/>
   <img border="0" src="//assets.pinterest.com/images/PinExt.png" title="Pin It" />
</h:outputLink>

这是陷阱:

• 整个标记是通过两种不同的bean的四种不同方法以及一些静态文本的组合来创建的
• 显然需要对url参数进行urlencode编码，因此我在h:outputLink中使用f:param以便对它们进行urlencode编码
• 生成的a标签需要具有非标准的count-layout="horizontal"属性

• the whole markup is created from the combination of four different methods from two different beans as well as some static text
• the url parameters obviously need to be urlencoded, therefore I am using f:param inside h:outputLink so that they get urlencoded
• the generated a tag needs to have the non-standard count-layout="horizontal" attribute

现在我的问题是以下情况之一:

• 如何将count-layout属性注入h:outputLink或生成的锚标记中
• 否则，如果我做不到，那么完成所需的pinit按钮标记的另一种非侵入性(我不想更改bean方法)的方法是什么?

所需的标记可以在 http://pinterest.com/about/goodies/中找到在将其固定在网站上的按钮"部分中.

The required markup can be found at http://pinterest.com/about/goodies/ down in the "pin it button for websites" section.

推荐答案

要么使用普通的<a>元素，同时使用

Either use a normal <a> element along with a custom EL function which delegates to URLEncoder#encode().

<c:set var="url" value="#{beanOne.someMethod}/sometext#{prettyContext.requestURL.toURL()}"/>
<c:set var="media" value="#{beanOne.someOtherMethod}/sometext/somemoretext/#{beanTwo.someMethodTwo}-some-text.jpg"/>
<c:set var="description" value="#{beanTwo.someOtherMethodTwo}"/>

<a href="http://pinterest.com/pin/create/button/?url=#{utils:encodeURL(url)}&amp;media=#{utils:encodeURL(media)}&amp;description=#{utils:encodeURL(description)}" class="pin-it-button" count-layout="horizontal">
   <img border="0" src="//assets.pinterest.com/images/PinExt.png" title="Pin It" />
</a>

(请注意，class属性对于<h:outputLink>无效，您应该使用styleClass)

(note that the class attribute was invalid for <h:outputLink>, you should be using styleClass)

或为<h:outputLink>创建自定义渲染器，以添加对count-layout属性的支持.假设您使用的是Mojarra，最简单的方法就是扩展其OutputLinkRenderer:

Or create a custom renderer for <h:outputLink> which adds support for count-layout attribute. Assuming that you're using Mojarra, simplest would be to extend its OutputLinkRenderer:

public class ExtendedLinkRenderer extends OutputLinkRenderer {

    @Override
    protected void writeCommonLinkAttributes(ResponseWriter writer, UIComponent component) throws IOException {
        super.writeCommonLinkAttributes(writer, component);
        writer.writeAttribute("count-layout", component.getAttributes().get("count-layout"), null);
    }

}

要使其运行，请在faces-config.xml中进行如下注册:

To get it to run, register it as follows in faces-config.xml:

<render-kit>
    <renderer>
        <component-family>javax.faces.Output</component-family>
        <renderer-type>javax.faces.Link</renderer-type>
        <renderer-class>com.example.ExtendedLinkRenderer</renderer-class>
    </renderer>
</render-kit>

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