FactoryGirl:填充一个具有很多关系的保存构建策略 [英] FactoryGirl: Populate a has many relation preserving build strategy

问题描述

我的问题似乎很普遍，但是我在文档或互联网本身中找不到任何答案.

My problem seems very common, but I haven't found any answer in the documentation or the internet itself.

似乎是这个问题的克隆 has_many，同时尊重在factory_girl中建立策略，但是在那之后的2.5年中，factory_girl发生了很大变化.

It might seem a clone of this question has_many while respecting build strategy in factory_girl but 2,5 years after that post factory_girl changed a lot.

我有一个具有has_many关系的模型，称为照片.我想填充这与保留我选择的构建策略有很多关系.

I have a model with a has_many relation called photos. I want to populate this has many relation preserving my choice of build strategy.

如果我打电话给offering = FactoryGirl.build_stubbed :offering, :stay，我希望offering.photos是存根模型的集合.

If I call offering = FactoryGirl.build_stubbed :offering, :stay I expect offering.photos to be a collection of stubbed models.

我发现实现这一目标的唯一方法是:

The only way i've found to achieve this is this one:

factory :offering do
  association :partner, factory: :named_partner
  association :destination, factory: :geolocated_destination

  trait :stay do
    title "Hotel Gran Vía"
    description "Great hotel in a great zone with great views"
    offering_type 'stay'
    price 65
    rooms 70
    stars 4
    event_spaces 3
    photos do
      case @build_strategy
      when FactoryGirl::Strategy::Create then [FactoryGirl.create(:hotel_photo)]
      when FactoryGirl::Strategy::Build then [FactoryGirl.build(:hotel_photo)]
      when FactoryGirl::Strategy::Stub then [FactoryGirl.build_stubbed(:hotel_photo)]
      end
    end
  end
end

不用说它必须存在一种更好的方法.

No need to say that IT MUST EXIST a better way of do that.

想法?

推荐答案

以下是Flipstone答案的较简洁版本:

Here's a slightly cleaner version of Flipstone's answer:

factory :offering do
  trait :stay do
    ...
    photos do
      association :hotel_photo, :strategy => @build_strategy.class
    end
  end
end

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