！empty(trim($ _ POST ['username'] [英] !empty(trim($_POST['username']

问题描述

好吧，问题是当我使用trim函数时不起作用，但是当我运行没有trim函数的代码时，它起作用了，但是却不能正常工作(表单接受空格)

Ok the problem is that when i use the trim function doesnt work but when i run the code without the trim function its working, but not properly working(the form accepts whitespaces)

<?php
session_start();
unset($_SESSION['username']);

 if (isset($_SESSION['username']))
    {echo "You are in already";}

 else if ($_SERVER['REQUEST_METHOD'] == 'POST')
 {      

 if (!empty(trim($_POST['username'])) && !empty(trim($_POST['email'])))
    {
        $uname = htmlentities($_POST['username']);
        $email = htmlentities($_POST['email']);
  $_SESSION['username'] = $uname;

            echo "THANKS: " . $uname . "<br />";
    }
 else { echo "fill the goddemn field"; }


  } else { ?>

<form action="index.php" method="post">
 <label for="username">USERNAME:</label>
 <input type="text" name="username" />
 <label for="E-MAIL">E-mail:</label>
 <input type="text" name="email" />
 <input type="submit" value="Enter" />
</form>


<?php    } ?>

我尝试了手册 http://php.net/manual/en/function. trim.php ，但是很难阅读，我什么也没弄清楚.

I tried the manual http://php.net/manual/en/function.trim.php but it was hard to read and I didn't figure out anything.

推荐答案

如 PHP手册所述:

空-确定变量是否为空

在您的情况下，trim是函数调用，而不是变量.

In your case, trim is a function call, not a variable.

<罢工> 如果您真的想内嵌if语句，则可以使用类似以下内容的

If you really want to do your if statement inline, you can use something like:

if (!empty($var=trim($_POST['username'])) && !empty($var=trim($_POST['email'])))

但是更好的实现应该是:

But a better implementation should be:

$username = array_key_exists('username', $_POST) ? trim($_POST['username']) : null;
$email = array_key_exists('email', $_POST) ? trim($_POST['email']) : null;

if (!empty($username) && !empty($email))
{
    (...)

这篇关于！empty(trim($ _ POST ['username']的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！