fgets在输入末尾添加\ 0或\ n吗? [英] fgets adds \0 or \n at the end of the input?

问题描述

我对fgets有一些疑问.据我所知，它在字符串的末尾添加了"\ n"，而不是"\ 0".因此，如果我编写这段代码:

I've some doubts about fgets. From what I know, it adds "\n" at the end of the string, and not "\0". So if I write this code:

fgets(buff,2,stdin);
printf("%s",buff);

因此fgets读取两个字符，我将输入"y"作为输入，因此buff应该为"y \ n".我希望printf打印y并添加一行，而它打印"y"而不添加一行.你能解释为什么吗?

So fgets reads two characters, I give as input "y", so buff should be "y\n". I'd expect printf to print y and add a line, while it prints "y" without adding a line. Can you explain why?

推荐答案

char * fgets ( char * str, int num, FILE * stream );

从输入流中读取字符，并将它们作为C字符串存储到str中，直到已读取(num-1)个字符或到达换行符或到达文件末尾为止，以先发生的为准.

Reads characters from input stream and stores them as a C string into str until (num-1) characters have been read or either a newline or the end-of-file is reached, whichever happens first.

换行符使fgets停止读取，但是该函数将其视为有效字符并包含在复制到str的字符串中.

A newline character makes fgets stop reading, but it is considered a valid character by the function and included in the string copied to str.

在复制到str的字符之后会自动附加一个终止的空字符('\ 0').

A terminating null character ('\0') is automatically appended after the characters copied to str.

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