在读取文件期间用单个换行符替换多个换行符 [英] Replace multiple newlines with single newlines during reading file

问题描述

我有下一个代码，该代码从多个文件读取，解析获得的行并打印结果:

I have the next code which reads from multiple files, parses obtained lines and prints the result:

import os
import re

files=[]
pars=[]

for i in os.listdir('path_to_dir_with_files'):
    files.append(i)

for f in files:
    with open('path_to_dir_with_files'+str(f), 'r') as a:
       pars.append(re.sub('someword=|\,.*|\#.*','',a.read()))

for k in pars:
   print k

但是我在输出中有多个新行的问题:

But I have problem with multiple new lines in output:

test1


test2

相反，我想获得下一个结果，输出中不包含空行:

Instead of it I want to obtain the next result without empty lines in output:

 test1
 test2

以此类推.

我尝试过使用regexp:

I tried playing with regexp:

pars.append(re.sub('someword=|\,.*|\#.*|^\n$','',a.read()))

但是它不起作用.我也尝试使用strip()和rstrip()包括replace.这也行不通.

But it doesn't work. Also I tried using strip() and rstrip() including replace. It also doesn't work.

能请你帮忙吗?

推荐答案

您可以使用第二个正则表达式用一个新行替换多个新行，并使用strip摆脱最后一个新行.

You could use a second regex to replace multiple new lines with a single new line and use strip to get rid of the last new line.

import os
import re

files=[]
pars=[]

for i in os.listdir('path_to_dir_with_files'):
    files.append(i)

for f in files:
    with open('path_to_dir_with_files/'+str(f), 'r') as a:
        word = re.sub(r'someword=|\,.*|\#.*','', a.read())
        word = re.sub(r'\n+', '\n', word).strip()
        pars.append(word)

for k in pars:
   print k

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