PHP在获取文件内容之前评估代码 [英] php evaluate code before getting file content

问题描述

我有一个文件B590.php，其中包含很多html代码和一些php代码(例如，登录的用户名，用户详细信息).

I have a file B590.php which is having a lot of html code and some php code (eg logged in username, details of user).

我尝试使用$html = file_get_content("B590.php");

但是$html然后将B90.php的内容作为纯文本(带有php代码).

But then $html will have the content of B90.php as plain text(with php code).

是否有任何方法可以在评估文件后获取文件的内容? 似乎有许多相关问题，例如此问题和

Is there any method where I can get the content of the file after it has been evaluated? There seems to be many related questions like this one and this one but none seems to have any definite answer.

推荐答案

    function get_include_contents($filename){
      if(is_file($filename)){
        ob_start();
        include $filename;
        $contents = ob_get_contents();
        ob_end_clean();
        return $contents;
      }
      return false;
    }

    $html = get_include_contents("/playbooks/html_pdf/B580.php");

此答案最初发布在Stackoverflow

This answer was originally posted on Stackoverflow

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