从多个zip文件中读取数据并将其组合为一个 [英] Reading data from multiple zip files and combining them to one

问题描述

我想从比如说zip1，zip2，zip3，zip4的4个zip文件中读取数据.所有这些zip文件都是从称为"BigZip"的1个大zip文件中分离出来的.我想将zip文件合并为一个，然后比较1个bigzip文件与(zip1 + zip2 + zip3 + zip4)合并后的zip文件的字节大小是否匹配.当我合并4个zip文件的大小时，我得到的文件大小非常小.我在做什么错了?

I want to read data from lets say 4 zip files called zip1, zip2, zip3, zip4. All of these zip files are split from this 1 big zip file called "BigZip". I want to combine the zip files into one and then compare the bytes if the 1 bigzip file matches the size of bytes with the combined zip file of (zip1+zip2+zip3+zip4). I am getting a very small file size when I combine the size of 4 zip files. What am I doing wrong?

这是我的相同代码:

targetFilePath1，targetFilePath2，targetFilePath3，targetFilePath4属于4个zip文件的路径. sourceFilePath是BigZip文件的路径

targetFilePath1, targetFilePath2, targetFilePath3, targetFilePath4 belongs to path of 4 zip files. sourceFilePath is the path to BigZip file

class Test {


public static void main(String args[]) {

ZipOutputStream outStream = new ZipOutputStream(new FileOutputStream(sourceBigZip));

            readZip(sourceFilePath, targetFilePath1);
            readZip(sourceFilePath, targetFilePath2);
            readZip(sourceFilePath, targetFilePath3);
            readZip(sourceFilePath, targetFilePath4);
  outStream.close();
}

static void readZip(String sourceBigZip, String targetFile) throws Exception {
    ZipInputStream inStream = new ZipInputStream(new FileInputStream(targetFile));
    byte[] buffer = new byte[1024];
    int len = inStream.read(buffer);
    while (len != -1) {
        outStream.write(buffer, 0, len);
        len = inStream.read(buffer);
        System.out.print(len);
    }

    inStream.close();
}
}

推荐答案

创建一次ZipOutputStream并将其传递给readZip()方法，例如:

Create ZipOutputStream once and pass it to readZip() method, like:

public static void main(String args[]) {
    ZipOutputStream outStream = new ZipOutputStream(new FileOutputStream(sourceFilePath));
    readZip(outStream , targetFilePath1);
    readZip(outStream , targetFilePath2);
    readZip(outStream , targetFilePath3);
    readZip(outStream , targetFilePath4);
}

然后在处理将数据从一个zip复制到另一个zip时出现错误... 您需要像这样复制zip文件中的每个文件:

Then you have an error dealing with copying the data from one zip to another... You need to copy each file in the zip file like this:

static void readZip(ZipOutputStream outStream, String targetFile)
        throws Exception {
    ZipInputStream inStream = new ZipInputStream(new FileInputStream(
            targetFile));
    byte[] buffer = new byte[1024];
    int len = 0;

    for (ZipEntry e; (e = inStream.getNextEntry()) != null;) {
        outStream.putNextEntry(e);
        while ((len = inStream.read(buffer)) > 0) {
            outStream.write(buffer, 0, len);
        }
    }
    inStream.close();
}

}

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