如何在C中读取.exe [英] How to read .exe in c

问题描述

我正在做一个小的压缩程序的小项目.为此，我想读取一个文件，比如说一个.exe文件，然后逐个字符地对其进行解析，并使用一些简单的字典算法对其进行加密.

I'm on a little project of making a little compressor program. For that I want to read a file, say an .exe, and parse it char by char and use some simple dictionary algorithm to encrypt it.

我只是使用发现的简单代码来读取文件:

For reading the file I just thout in using a simple code I found:

 char *readFile(char *fileName)
{
    FILE *file;
    char *code = malloc(10000* sizeof(char));
    file = fopen(fileName, "rb");
    do
    {
      *code++ = (char)fgetc(file);

    } while(*code != EOF);

    return code;

}

我的问题是，似乎根本无法读取.exe或任何文件.当将printf()设为代码"时，不会写入任何内容.

My problem is that it's seems imposible to read an .exe or any file at all. When making a printf() of "code" nothing is writen.

我该怎么办?

推荐答案

@BLUEPIXY可以很好地识别代码错误.请参阅以下内容.另外，您返回字符串的结尾，并且可能想返回开头.

@BLUEPIXY well identified a code error. See following. Also you return the end of the string and likely want to return the beginning.

do {
  // *code++ = (char)fgetc(file);
  *code = (char)fgetc(file);
// } while(*code != EOF);
} while(*code++ != EOF);

让您开始阅读任何文件的方法.

Something to get you started reading any file.

#include <stdio.h>
#include <ctype.h>

void readFile(const char *fileName) {
  FILE *file;
  file = fopen(fileName, "rb");
  if (file != NULL) {
    int ch;
    while ((ch = fgetc(file)) != EOF) {
      if (isprint(ch)) {
        printf("%c", ch);
      }
      else {
        printf("'%02X'", ch);
        if (ch == '\n') {
          fputs("\n", stdout);
        }
      }
    fclose(file);
  }
}

按字符读取二进制文件时，代码通常接收0到255和EOF以及257个不同的值.

When reading a binary file char-by-char, code typically receives 0 to 255 and EOF, 257 different values.

这篇关于如何在C中读取.exe的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！