在Python中从文件名提取扩展名 [英] Extracting extension from filename in Python

问题描述

是否有从文件名中提取扩展名的功能?

Is there a function to extract the extension from a filename?

推荐答案

是.使用os.path.splitext(请参阅 Python 2.X文档或 Python 3.X文档) :

Yes. Use os.path.splitext(see Python 2.X documentation or Python 3.X documentation):

>>> import os
>>> filename, file_extension = os.path.splitext('/path/to/somefile.ext')
>>> filename
'/path/to/somefile'
>>> file_extension
'.ext'

与大多数手动字符串拆分尝试不同，os.path.splitext将正确地将/a/b.c/d视为没有扩展名而不是扩展名.c/d，并且将.bashrc视为没有扩展名而不是扩展名.bashrc :

Unlike most manual string-splitting attempts, os.path.splitext will correctly treat /a/b.c/d as having no extension instead of having extension .c/d, and it will treat .bashrc as having no extension instead of having extension .bashrc:

>>> os.path.splitext('/a/b.c/d')
('/a/b.c/d', '')
>>> os.path.splitext('.bashrc')
('.bashrc', '')

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