替代Process.Start() [英] Alternative to Process.Start()

问题描述

我刚刚完成了文档存储解决方案的编码，遇到了以下问题.在用户界面内，用户可以按一个按钮来打开文件:

I'm just finishing off coding a a document storage solution and I've run across the following issue. Within the UI the user can press a button to open a file:

try
{
    Process.Start(file);
}
catch (Exception ex)
{
    //Error handling code
}

我的问题是，如果用户没有与文件类型关联的应用程序，则会抛出componentmodel异常并显示一条消息.

My issue is that if the user has no application associated with the file type a componentmodel exception is thrown with a message to that effect.

我想做的是在这种情况下弹出打开方式"对话框，我是否缺少方法调用?

What I'd rather do is have the "Open with" dialog pop-up in that situation, is there a method call I'm missing?

推荐答案

有关使用打开方式"对话框的信息，请参见本文

See this article for using the Open With dialog

http://www.codeproject.com/KB/shell/openwith.aspx

我将把Process.Start调用放在try语句中，然后在捕获中显示打开方式".

I would put the Process.Start call in a try statement, and then show the "Open With" in the catch.

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