如何在bash脚本中使用包含文件名和空格的变量? [英] How do I use a variable containing a filename with spaces in a bash script?

问题描述

我在OS X上运行了一个简单的bash脚本，该脚本删除了特定的文件和目录，并在其位置复制了新的文件和目录.一个Mac .app目录包含一个空格，当我运行脚本时，出现没有这样的文件或目录"错误.

I have a simple bash script running on OS X that removes specific files and directories and copies new ones in their place. One Mac .app directory contains a space, and when I run the script there is a "No such file or directory" error.

这是相关的代码.已经淘汰了很多，所以不可能简单地对它们进行不同的硬编码(变量必须照原样分解):

Here is the relevant code. A good amount has been cut out, so simply hard coding these differently isn't possible (the variables must be broken up as they are):

CP="cp -Rf"

INSTALL_DIR="/Applications/"

APP="The App.app"

NEWAPP="$HOME/Downloads/The App.app"

$CP "$NEWAPP " "$INSTALL_DIR$NEWAPP"

我已经尝试了转义The\ App.app并没有运气，还尝试了单引号，双引号和双转义，但是没有任何效果.我想有一种简单的方法可以做到这一点.

I've tried escaping The\ App.app with no luck, as well as trying single quoting, double quoting, and double escaping, but nothing has worked. I imagine there is a simple way to do this.

感谢您的帮助.

推荐答案

您在那里有多余的空间，很简单

You have an extra space there, it's simply

"$ NEWAPP"

"$NEWAPP"

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