使用Shell脚本重命名多个文件 [英] Renaming multiple files using a Shell Script

问题描述

我有一个名为t1.txt，t2.tx t，t3.txt ... t4.txt的文件，我需要一个shell脚本来像这样重命名它:

I have files named t1.txt, t2.txt, t3.txt ... t4.txt and I need a shell script to rename it like this:

文件一:M.m.1.1.1.201108290000.ready

文件二:M.m.1.1.1.201108290001.ready

等等，后4位的序列号会更改.

etc, the sequence number in the last 4 digits changes.

如果有人帮助我，我将不胜感激:)

I'd be grateful if someone helped me :)

最好的问候

推荐答案

这可能是您需要的:

cd /home/me/Desktop/files/renam/
n=201108290000
for file in *.txt; do
    echo $file
    prefix=M.m.1.1.1.
    file_name=M.m.1.1.1.$n.ready
    echo $file_name
    n=$(( $n+1 ))
    mv $file $file_name
done

它与您自己编写的内容很接近，只是您错过了一些bash语法.请注意，您可能想更改n的初始值，否则对于您提到的t1.txt文件将变为M.m.1.1.1.201108290000.ready.根据您的用途，这可能会造成混淆.

It's close to what you'd written yourself, you just missed some bash syntax. Note that you might want to change the initial value of n, otherwise for the files you mentioned t1.txt would become M.m.1.1.1.201108290000.ready. Depending on what your use is, that might be confusing.

我还建议您避免将程序和内建函数的名称用作变量名，例如您的情况下为seq.

I'd also advice you to avoid use the names of programs and builtins as variable names, such as seq in your case.

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