在文件名中查找空格 [英] find with spaces in filename

问题描述

我经常将grep与find一起使用两次，以便在文件中搜索以下两种模式:

I often use grep twice with find in order to search for two patterns in a file as follows:

find . -name \*.xml | xargs grep -l "<beans" | xargs grep singleton

然后我碰到了带有空格的文件，这些文件当然破坏了上面的命令.我对它进行了如下修改以处理空格:

Then I ran into files with spaces which of course broke the above command. I modified it as follows to deal with the spaces:

find . -name \*.xml -print0 | xargs -0 grep -l "<beans" | xargs grep singleton

-print0选项告诉find使用print null作为分隔符而不是空格，而-0选项告诉xargs期望为null.只要我要查找的文件的路径中都没有空格，该方法就可以工作，但是如果有的话，它就会中断.

The option -print0 tells find to use print null as a separator instead of space and -0 tells xargs to expect a null. This works as long as none of the files I am looking for have spaces in their paths, but it breaks if they do.

所以我需要一个标志来告诉grep以speartor而不是换行符的形式输出null.

So what I need is a flag to tell grep to print null as a speartor instead of newline.

有什么想法吗?

推荐答案

好问题.您可以使用Z选项使grep -l使用空值作为分隔符:

Good question. You can make grep -l use nulls as a delimiter with the Z option:

find . -name \*.xml -print0 | xargs -0 grep -lZ "<beans" | xargs grep singleton

您还可以使xargs作为换行符来作为分隔符.这也应该起作用:

You can also make xargs us the newline character as a delimiter. That should work for too:

find . -name \*.xml -print0 | xargs -0 grep -l "<beans" | xargs "--delimiter=\n" grep singleton

第一个解决方案更好.

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