查找所有文件并将特定文件解压缩到本地文件夹 [英] Find all files and unzip specific file to local folder

问题描述

find -name archive.zip -exec unzip {} file.txt \;

此命令查找所有名为archive.zip的文件，并将file.txt解压缩到执行该命令的文件夹中，是否可以将文件解压缩到找到.zip文件的相同文件夹中?我希望将file.txt解压缩到folder1.

This command finds all files named archive.zip and unzips file.txt to the folder that I execute the command from, is there a way to unzip the file to the same folder where the .zip file was found? I would like file.txt to be unzipped to folder1.

folder1\archive.zip
folder2\archive.zip

我意识到$ dirname在脚本中可用，但是我正在寻找一个单行命令.

I realize $dirname is available in a script but I'm looking for a one line command if possible.

推荐答案

@iheartcpp-我使用相同的基本命令成功运行了三种选择...

@iheartcpp - I successfully ran three alternatives using the same base command...

find . -iname "*.zip"

...，用于提供/的列表作为参数传递给下一个命令.

... which is used to provide the list of / to be passed as an argument to the next command.

替代方法1:使用-exec + Shell脚本(unzips.sh)查找

Alternative 1: find with -exec + Shell Script (unzips.sh)

文件unzips.sh:

File unzips.sh:

#!/bin/sh
# This will unzip the zip files in the same directory as the zip are

for f in "$@" ; do
    unzip -o -d `dirname $f` $f
done

使用这种替代方法:

find . -iname '*.zip' -exec ./unzips.sh {} \;

替代2:使用| xargs _ Shell脚本(解压缩)查找

Alternative 2: find with | xargs _ Shell Script (unzips)

相同的unzips.sh文件.

使用这种替代方法:

find . -iname '*.zip' | xargs ./unzips.sh

替代3:同一行中的所有命令(无.sh文件)

使用这种替代方法:

find . -iname '*.zip' | xargs sh -c 'for f in $@; do unzip -o -d `dirname $f` $f; done;'

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当然，还有其他替代方法，但希望上述替代方法可以有所帮助.

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Of course, there are other alternatives but hope that the above ones can help.

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